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Y_Kistochka [10]
3 years ago
10

Simplify this equation 3m + 4 = -5

Mathematics
1 answer:
Tems11 [23]3 years ago
6 0
The solution to this is m=-3
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Explain how to determine the x- and y- intercepts of a line from a given equation in y = mx + b form.
NISA [10]

Answer:

Step-by-step explanation:

x-intercept:  Set y = 0 and solve for x:

 0 = mx + b, or mx = -b, or x = -b/m.  x-intercept is then (-b/m, 0)

y-intercept:  Set x = 0 and solve for y:  y = m(0) + b, or y = b.  y-intercept is then

 (0, b).

3 0
3 years ago
F(x)=(x+4)(x-2)(x+4)(x+4)<br><br> What is the multiple zero? Multiplicity is?
kari74 [83]
f(x)=(x+4)(x-2)(x+4)(x+4)\\f(x)=(x+4)^3(x-2)=0\\(x+4)^3=0~|~(x-2)=0\\(x+4)(x+4)(x+4)=0~|~x=2\\x=-4,2

The multiple zero is x = -4.

The multiplicity is 2 because there are two values of x.
8 0
3 years ago
Can anyone solve this?
Elis [28]

Answer:

X = 4

Y = 30

i think.

Step-by-step explanation:

3 0
3 years ago
A window is being replaced with tinted glass. The plan at the right shows the design of the window. Each unit length represents
PolarNik [594]
The answer is $911.68.

After a little research on the internet, I found the design of the window.
First, you need to find the area of the window which is a composite figure made up of a rectangle and a circle. So, the total area (A) is the sum of the area of the rectangle (A1) and the area of the circle (A2).

Area of the rectangle with length l and width w is:
A = l * w
According to the image, l = 5 ft and w = 4 ft.
A1 = 5 * 4 = 20 ft²

Area of the circle with radius r is:
A = r²π
According to the image, r = 2 ft.
A2 = 2² * 3.14 = 12.56 ft²

The area of the window is:
A = A1 + A = 20 ft² + 12.56 ft² = 32.56 ft²

<span>The glass costs $28 per square foot, so to replace the glass will cost:
</span>32.56 ft² * $28/ft² = $911.68
7 0
4 years ago
Vertical structural members that exterior wall sheathing and siding may be attached to are called
DENIUS [597]

Studs is the answer to this question.

Vertical structural members are called Studs. This is the term which is used in construction. There are exterior and interior walls which are framed, these walls are known as bearing walls, and some are also non- bearing. Whenever there is foundation in a place, after the first floor deck these bearing walls are formed.

7 0
3 years ago
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