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Y_Kistochka [10]
3 years ago
10

Simplify this equation 3m + 4 = -5

Mathematics
1 answer:
Tems11 [23]3 years ago
6 0
The solution to this is m=-3
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X^2 - 9x -10 =0 has a discriminant of: a. 121 b. 72 c. -359 d. 41 e. 136
Feliz [49]
In the standard form of quadratic
ax^{2} +bx+c
the discriminant is
b^{2} -4ac
In your quadratic, a = 1, b = -9 and c = -10
Now you need to plug these values into the expression for the discriminant.
7 0
3 years ago
What is 38/439 reduced
Lemur [1.5K]

Answer:

Step-by-step explanation:

You divide 38 by 439 and your answer is around 0.8656

6 0
3 years ago
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You run 4 miles each week each week. On monday, you run 1/2 mile.on Tuesday you run 1/3 mile. How much farther do you run on Mon
Pepsi [2]
To solve this problem, let's use subtraction :)

1/2 - 1/3 = 3/6 - 2/6
               = 1/6

Therefore, on monday you ran 1/6 more than Tuesday. 

Hope this helps!
7 0
3 years ago
Look at image.............
Tasya [4]

Answer:

answer is -3 ....is this correct

4 0
2 years ago
An alloy of tin is 15% tin and weighs 20 pounds. A second alloy is 10% tin. How many pounds of the second alloy must be added to
katovenus [111]
So, they alloy is hmmm some piece of metal.

it has tin, among other metals, regardless of what other metals it may have, we know that for the first one, 15% is tin, the rest something else, and we also know that the alloy itself, weights 20 lbs.

now, how much is just the weight of the tin metal in it alone?  well, is 15% of 20 lbs, or (15/100) * 20, or 3 lbs, so of all those 20 lbs, only 3 lbs or 15% is tin.

for the second alloy, let's say we'll add "x" lbs, we know the second alloy is 10% tin, how much of that weight is tin?  well 10% of x, or (10/100) * x, or 0.10x lbs.

now, we're looking for a mixture, say the resulting lbs of mix will be "y" lbs, and we know the mixture will be 12% of tin, how much is 12% of y?  (12/100) * y, or 0.12y.

now, regardless of what "x" and "y" is, we know that 20 + x = y, and that 3 + 0.10x = 0.12y, thus

\bf \begin{array}{lccclll}
&\stackrel{lbs}{amount}&\stackrel{tin~\%}{quantity}&\stackrel{tin~lbs}{quantity}\\
&------&------&------\\
\textit{15\% alloy}&20&0.15&3\\
\textit{10\% alloy}&x&0.10&0.10x\\
------&------&------&------\\
mixture&y&0.12&0.12y
\end{array}
\\\\\\
\begin{cases}
20+x=\boxed{y}\\
3+0.10x=0.12y\\
----------\\
3+0.10x=0.12\left( \boxed{20+x} \right)
\end{cases}
\\\\\\
3+0.10x=2.4+0.12x\implies 3-2.4=0.12x-0.10x
\\\\\\
0.6=0.02x\implies \cfrac{0.6}{0.02}=x\implies 30=x
4 0
4 years ago
Read 2 more answers
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