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3 years ago

Someone help pls <<<

Mathematics

1 answer:

Pepsi [2]3 years ago

7 0

Answer:

Choose and hope. I think its the first one. But its 50/50.

Step-by-step explanation:

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PLEASE HELP WITH QUESTION. 18 POINTS THANKS SO MUCH

-BARSIC- [3]

Answer:

The Red Submersible

Step-by-step explanation:

8 0

3 years ago

PLEASE ANSWER<br> Given the domain {-4, 0, 5}, what is the range for the relation y = -2x + 4?

maw [93]

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$y = f(x) = - 2x + 4$

_________________________________

$f( - 4) = - 2( - 4) + 4$

$f( - 4) = 8 + 4$

$f( - 4) = 12$

_________________________________

$f(0) = - 2(0) + 4$

$f(0) = 0 + 4$

$f(0) = 4$

_________________________________

$f(5) = - 2(5) + 4$

$f(5) = - 10 + 4$

$f(5) = - 6$

_________________________________

Thus ;

Range = { -6 , 4 , 12 }

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5 0

3 years ago

Read 2 more answers

Find the Surface Area of the rectangular prisms with the given measures.

Kaylis [27]

Answer: 1.=336m

2.=276.4ft

3.=889in

4.=2.58mi

5.= 4042mm

Step-by-step explanation:

5 0

3 years ago

Determine the volume of the figure that has a radius of 2 feet. Round your answer to nearest tenth of a cubic foot

Sindrei [870]

Answer: 138.2 ft³

Step-by-step explanation:

The area of the figure is:

$V_f=V_{cylinder}+V_{cone}$

Calculte the volume of the cylinder:

$V_{cylinder}=hr^2\pi$

Where r is the radius ( $r=2ft$ ) and h is the height.

Then:

$V_{cylinder}=(10ft)(2ft)^2\pi=125.66ft^3$

Calculte the volume of the cone:

$V_{cone}=\frac{1}{3}hr^2\pi$

Where r is the radius ( $r=2ft$ ) and h is the height.

Then:

$V_{cone}=\frac{1}{3}(3ft)(2ft)^2\pi=12.56ft^3$

Therefore:

$V_f=125.66ft^3+12.56ft^3=138.2ft^3$

8 0

3 years ago

The complex solutions of which equation have a real component of 4?

Naddik [55]

Answer:

the answer is B do you need me to show work?

6 0

3 years ago