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astraxan [27]
3 years ago
6

What is the range and domain of (-3,-22) (-2,-8) (-1,2) (0,8)) (1,10) (2,8) (3,2)​

Mathematics
1 answer:
BartSMP [9]3 years ago
3 0

Answer:

Step-by-step explanation:

domain is x component so

domain = {-3 , -2 , -1 , 0 , 1 , 2 , 3 }

range is y component so

range = { -22 , -8 , 2 , 8 , 10 , 2 }

note : repeated element can be written only one time. For eg here in range 8 is 2 times but we can write only one time because it is the rule for lisying range and domain.

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don't lose your hope

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I will mark u brainlist if u answer find the mistake... 4x + x = 30 –6 4x = 24 4 24 4 4 x x = 6
Jlenok [28]

Answer:

The mistake is that 4x+x = 5x  not 4x

Step-by-step explanation:

4x + x = 30 –6

Combine like terms

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Divide each side by 5

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x = 24/5

The mistake is that 4x+x = 5x  not 4x

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Find the product: (50z + 20)(10z + 4) ( 1 ) 12. Find the product: (88a + 80)(8a + 8)
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Answer:

1. 60z, 36

2. 96a, 88

Step-by-step explanation:

1.

First, find the like terms for z. (60z)

Second, find the like terms for 20, 4, and 12. (36)

2.

Combine the 88a and 8a (96a)

Then combine 8 plus 80 (88)

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3 years ago
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Gena wants to estimate the quotient of –21.87 divided by 4.79. Which expression shows the best expression to estimate the quotie
Mkey [24]

Answer:

-20 divided 5 is the right answer.

Your welcome!

Step-by-step explanation:

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3 years ago
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On the first of each month, Shelly runs a 5k race. She keeps track of her times to track her progress. Her time in minutes is re
Vikki [24]

Answer:

C . 0.76

Step-by-step explanation:

We are given that on the first of each month , Shelly runs a 5 k race. She keeps track of her times to track her progress. Her time in minutes is recorded in the table:

Jan  40.55 Feb 41.51

March 42.01 Apr 38.76

May 36.32  June 34.28

July 35.38  Aug 37.48

Sept 40.87 Oct 48.32

Nov 41.59 Dec 42.71

We have to find the difference between the mean of the data , including the outlier and excluding the outlier

Outlier: That observation which is different from other observations.

The outlier in the given observations is 48.32 because is different from other observations.

Mean of the data including the outlier

Mean =\frac{Sum \;of\;observations}{Total\;number\;of\;observations}

Mean=\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+48.32+41.59+42.71}{12}

Mean=\frac{479.78}{12}

Mean=39.982

Mean of the data excluding the outlier

Mean=\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+41.59+42.71}{11}Mean=[tex]\frac{431.46}{11}

Mean=39.224

Difference between mean of the data including the outlier and excluding the outlier=39.982-39.224=0.758

Difference between mean of the data including the outlier and excluding the outlier=0.76

Answer Answer:

Step-by-step explanation:

We are given that on the first of each month , Shelly runs a 5 k race. She keeps track of her times to track her progress. Her time in minutes is recorded in the table:

Jan  40.55 Feb 41.51

March 42.01 Apr 38.76

May 36.32  June 34.28

July 35.38  Aug 37.48

Sept 40.87 Oct 48.32

Nov 41.59 Dec 42.71

We have to find the difference between the mean of the data , including the outlier and excluding the outlier

Outlier: That observation which is different from other observations.

The outlier in the given observations is 48.32 because is different from other observations.

Mean of the data including the outlier

Mean =\frac{Sum \;of\;observations}{Total\;number\;of\;observations}

Mean=\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+48.32+41.59+42.71}{12}

Mean=\frac{479.78}{12}

Mean=39.982

Mean of the data excluding the outlier

Mean=\frac{40.55+41.51+42.01+38.76+36.32+34.28+35.38+37.48+40.87+41.59+42.71}{11}Mean=[tex]\frac{431.46}{11}

Mean=39.224

Difference between mean of the data including the outlier and excluding the outlier=39.982-39.224=0.758

Difference between mean of the data including the outlier and excluding the outlier=0.76

Answer :C . 0.76

5 0
3 years ago
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