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Viktor [21]
3 years ago
6

What is the system of inequalities associated with the following graph?

Mathematics
2 answers:
Alex17521 [72]3 years ago
8 0

Answer: d

Step-by-step explanation:

slamgirl [31]3 years ago
6 0

One line passes through the points (-2,3) and (0,-3) , it means the y intercept is b=-3

and slope m = \frac{(-3-3)}{0-(-2)}

= \frac{-6}{2}= -3

So the equation of line will be y= -3x -3

And the inequality should be y\geq -3x-3

Or 3x +y \geq -3

And the other line passes through (-2,3) and (0,2)

So the y intercept is b=2

and the slope is m= \frac{2-3}{0-(-2)} = \frac{-1}{2}

So the equation of line will be y= \frac{-1}{2} x +2\\and the inequality should be  y \leq \frac{-1}{2} x+2

Or

2y +x \leq 4

So answer is 3x +y \geq -3,  x+2y\leq 4

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Solve the equation. x2 18x 81 = 25<br> a. 14, 4<br> b. –4, –14<br> c. 14, –14<br> d. –4, 4
Snowcat [4.5K]

Answer:

The answer is the option B

-4,-14

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2}+18x+81=25  

x^{2}+18x+56=0  

so

a=1\\b=18\\c=56

substitute in the formula

x=\frac{-18(+/-)\sqrt{18^{2}-4(1)(56)}} {2(1)}

x=\frac{-18(+/-)\sqrt{100}} {2}

x=\frac{-18(+/-)10} {2}

x1=\frac{-18+10} {2}=-4

x2=\frac{-18-10} {2}=-14

7 0
3 years ago
Read 2 more answers
A rectangle has length represented as (R +5) and width represented as (R + 2).
svetlana [45]

Answer:

4(R + 5 + R + 2) [Option B]

Step-by-step explanation:

<u>GIVEN :-</u>

  • Length = R + 5
  • Width = R + 2

<u>TO FIND :-</u>

  • Perimeter of the rectangle

<u>FORMULAE TO BE USED :-</u>

For a rectangle with length 'l' and width 'w' , its perimeter = 4(l + w)

<u>SOLUTION :-</u>

Perimeter = 4(R + 5 + R+2)

                 = 4(2R + 7)

                 = 8R + 14

7 0
2 years ago
Please help I will give brainliest
Katyanochek1 [597]

Answer:

30 in^2

Step-by-step explanation:

The formula for finding the area of a trapezoid is A=a+b/2 x h

In this case, a=5, b=10, and h=4

When you input those values into the formula and solve for A, you get A=30

Please mark as brainliest ;)

3 0
2 years ago
An airplane spots the floating debris at an angle of depression of 15 degrees. If the plane is at an altitude of 3000. Feet, wha
hodyreva [135]

Answer:

11196.15 km

Step-by-step explanation:

Consider the attached diagram

If the Airplane is at point A and the floating debris at point C, we want to determine the horizontal distance |AB| before they fly over it.

Using trigonometry

Tan \alpha =\frac{Opposite}{adjacent} \\Tan 15 =\frac{3000}{|AB|}

Cross multiply

|AB|X Tan 15 =3000

|AB| = \frac{3000}{Tan 15} =11196.15 km

Therefore, the horizontal distance |AB| before they fly over it is 11196.15 km

6 0
3 years ago
During his first vet visit, Pedro’s puppy weighed 6 1/8 pounds. On his second visit, he weighed 9 1/16 pounds. How much did he g
IceJOKER [234]
2 15/16 I think! hope it helps
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