Question Progres

The class decides to make chocolate chip cookies for Mr. Burn’s first day of school in September. Each student needs 3⁄4 of a st

VladimirAG [237]

Answer:

10 1/2 sticks, or 11 sticks with half a stick left over.

Step-by-step explanation:

If every student (and there are 14 students) needs 3/4 stick of butter, the equation is 3/4 x 14 = 10 1/2

3 0

3 years ago

Which equation is correct

Sergeeva-Olga [200]

1. Two of the main identities used in trigonometry for right triangles (Triangles that have an angle of 90°) are: Sine (Sin) and Cosine (Cos).

Sin x°=Opposite/Hypotenuse

Cos x°=Adjacent/Hypotenuse

2. The inverse of Sinx° is Cosec x°, then:

Cosec x°=1/Sin x°

3. The inverse of Cos x° is Sec x°, then:

Sec x°=1/Cos x°

4. Keeping this on mind, you have:

Cosc x°=Hypotenuse/Opposite

Sec x°=Hypotenuse/Adjacent

5. Therefore, the correct answer is:

The third option: Cosec x°=Hypotenuse/Opposite.

7 0

3 years ago

Read 2 more answers

Lizzy wants to solve the equation 6(2x + 1) = 4x – 5. Which step would be an appropriate first step for Lizzy to take to solve f

e-lub [12.9K]

Answer:

distribute parenthesis

Step-by-step explanation:

6(2x + 1) = 4x - 5 ← distribute parenthesis on left side

12x + 6 = 4x - 5 ( subtract 4x from both sides )

8x + 6 = - 5 ( subtract 6 from both sides )

8x = - 11 ( divide both sides by 8 )

x = - $\frac{11}{8}$

7 0

3 years ago

Given the function f(x) = 3|x – 2| + 6, for what values of x is f(x) = 18?

Gwar [14]

Answer:

x = - 2, x = 6

Step-by-step explanation:

Given f(x) = 18 we require to solve

3 | x - 2 | + 6 = 18 ( subtract 6 from both sides )

3 | x - 2 | = 12 ( divide both sides by 3 )

| x - 2 | = 4

The absolute value function always returns a positive value, however, the expression inside can be positive or negative, thus

x - 2 = 4 ( add 2 to both sides )

x = 6

OR

- (x - 2) = 4

- x + 2 = 4 ( subtract 2 from both sides )

- x = 2 ( multiply both sides by - 1 )

x = - 2

As a check substitute these values into the left side of the equation and if equal to the right side then they are the solutions

x = 6 → 3|6 - 2| + 6 = 3|4| + 6 = 3(4) + 6 = 12 + 6 = 18 ← True

x = - 2 → 3|- 2 - 2| + 6 = 3|-4| + 6 = 3(4) + 6 = 12 + 6 = 18 ← True

Hence solutions are x = - 2, x = 6

7 0

3 years ago

Read 2 more answers

The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo

PolarNik [594]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY = $\sqrt{x^2+y^2}$

Therefore, the length between points AB is

length AB = $\sqrt{(-4 - (-2))^2+(-1-3)^2}$

= $\sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2} = \sqrt{20}$ = 4.472 units

Similarly, length BC is given by

Length BC = $\sqrt{(-4)^2+1^2} = \sqrt{17}$ = 4.123 units

Length CD = $\sqrt{(-2)^2+5^2} = \sqrt{29}$ = 5.385 units

Length DA = $\sqrt{(8)^2+(-2)^2} = \sqrt{68}$ = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A = $\sqrt{(7)^2+(0)^2} = \sqrt{49}$ =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

$S_{\bigtriangleup}$ = $(\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|$

= $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

$S_{{\bigtriangleup}ABC}$ = $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

$=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|$

= $=(\frac{1}{2})|-4-6 -8|= 9 units^2$

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

$S_{{\bigtriangleup}ACD'}$ = $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

$=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2}$ = 10.5 units²

Area of polygon = $S_{{\bigtriangleup}ABCD'}$ = $S_{{\bigtriangleup}ABC}$ + $S_{{\bigtriangleup}ACD'}$ = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

8 0

4 years ago