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astraxan [27]
2 years ago
10

Help plz i need this done

Mathematics
1 answer:
Romashka [77]2 years ago
5 0

Answer:

x ≈ 11.5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Trigonometry</u>

  • [Right Triangles Only] SOHCAHTOA
  • [Right Triangles Only] sin∅ = opposite over hypotenuse

Step-by-step explanation:

<u>Step 1: Identify Variables</u>

Angle = 35°

Opposite Leg = <em>x</em>

Hypotenuse = 20

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute [sine]:                    sin35° = x/20
  2. Isolate <em>x</em>:                                 20sin35° = x
  3. Evaluate:                                 11.4715 = x
  4. Rewrite:                                  x = 11.4715
  5. Round:                                    x ≈ 11.5
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Strike441 [17]

Answer:

y=4x+5

Step-by-step explanation:

so like the b in y= mx +b is the starting point well in that graph it is also is where the line touches the y-axis and the slope is rise/run so start at 5 move over 1 then go up 4 that 4/1 = 4 so m=4 so if y= 4x+b and b being 5 then y=4x+5

3 0
3 years ago
Read 2 more answers
Ben was walking in Manhattan at a constant speed. He went along 5th avenue from 4th to 98th street. At 3:00 he was on 15th stree
muminat

Answer: The starting time is 2:27 and finishing time is 7:09.    


Step-by-step explanation: It is given that Ben started from 4th street and he finished at 98th street.

Also, at 3:00, he was on 15th street and at 4:30, he was on 45th street.

That is, time taken to cover (45-15), i.e., 30 streets is 90 minutes,                           so the time taken to cover 1 street is 3 minutes.

Therefore, Ben covers distance from one street to second in 3 minutes. Since he started from 4th street, and there are 11 streets to cover between 4 and 15, so Ben's starting time was (3:00 - 3×11 min) = 2:27.

And his finishing time was (4:30 + 3×53 min) = 7:09.

Again, the equation that tells us on what street 'N' he was after time 'T' of his starting can be written as

N=4+\dfrac{T}{3.}

Thus, the starting and finishing time was 2:27 and 7:09 respectively.



3 0
3 years ago
NEED HELP MY GRADE DEPENDS ON THIS!!!
ss7ja [257]
28x - 2 = 26x + 6
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2 years ago
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