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Cloud [144]
3 years ago
8

Output each floating-point value with two digits after the decimal point, which can be achieved by executing cout << fixed

<< setprecision(2); once before all other cout statements.(1) Prompt the user to enter five numbers, being five people's weights. Store the numbers in a vector of doubles. Output the vector's numbers on one line, each number followed by one space. Enter weight l: 236.0 Enter weight 2: 89.5 Enter weight 3: 142.0 Enter weight 4: 166.3 Enter weight 5: 93.0 You entered: 236.00 89.50 142.00 166.30 93.00 (2) Also output the total weight, by summing the vector's elements.(3) Also output the average of the vector's elements. (4) Also output the max vector element. EX Enter weight 1: 236.0 Enter weight 2: 89.5 Enter weight 3: 142.0 Enter weight 4: 166.3 Enter weight 5: 93.0 You entered: 236.00 89.50 142.00 166.30 93.00 Total weight: 726.80 Average weight: 145.36 Max weight: 236.00
Computers and Technology
1 answer:
WINSTONCH [101]3 years ago
3 0
Hi it’s 24 and brown is the next
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6 0
4 years ago
Convert the decimal number 164 into the equivalent 8 bit binary number. ​
umka2103 [35]

Answer:

10100100

Explanation:

8 bit system consists of 8 bits or 8 positions and each of them can have binary value (0 or 1).

Each bit is equivalent to a certain power of number 2. Important to know is that you read these bits from right to left.

So, this means that the bit furthest to the right has the value of 2^0, which is 1. The bit to the left has the value of 2^1, which is 2. Next one is 2^2, which is 4 etc. This means that the bit furthest to the left has the value of 2^7, which is 128.

The bit has this potential value only if value 1 if is in its position. If the value is 0 then, regardless of position, value of the bit is 0.

Decimal value of the number is calculated when we add all the values of the bits marked with 1.

So, we're dealing with number 164. We already said that leftmost bit has the value of 128 if it's marked with 1:

1 0 0 0 0 0 0 0 = 128

Next bit has the value of 64, but 128+64 would exceed the value of our number, so the second leftmost bit remains 0.

Next bit has the value of 32, 128+32 is 160, which is less then our number, so we mark the third bit with 1:

1 0 1 0 0 0 0 0 = 160

Similarly, we continue down the line. We only need 4 to reach the value of our number, so we'll mark with 1 the bit that has the value of 4, which leaves us with the solution:

1 0 1 0 0 1 0 0 = 164

7 0
3 years ago
The Sarbanes-Oxley Act restricts electronic and paper data containing personally identifiable financial information.A. True
Zarrin [17]

Answer:

B. False

Explanation:

Sarbanes-Oxley Act or SOX also known as the Public Company Accounting Reform and Investor Protection Act and Corporate and Auditing Accountability, Responsibility, and Transparency Act is a United State federal law that creates or modify requirements for U.S public company board, management and public accounting firm. some of its policies are meant for private companies as well.

This act does not restrict any electronic and paper data containing personally identifiable financial information.

6 0
4 years ago
Virtual machines are not susceptible to the threats and malicious attacks like other operating systems.
Nonamiya [84]

Answer:

flamingo was here

Explanation:

3 0
3 years ago
Create a function called makePositive that accepts a single argument: an integer array. The function should walk through the arr
coldgirl [10]

Answer:

This solution is implemented in C++

void makePositive(int arr[]){

   int i =0;

   while(arr[i]!=0){

       if(arr[i]<0){

           arr[i] = abs(arr[i]);

       }

       i++;

   }

   i = 0;

   while(arr[i]!=0){

    cout<<arr[i]<<" ";

    i++;

}  

}

Explanation:

This defines the function makePositive

void makePositive(int arr[]){

This declares and initializes i to 0

   int i =0;

The following iteration is repeated until the last element in the array

   while(arr[i]!=0){

This checks if current array element is negative

       if(arr[i]<0){

If yes, it changes it to positive

           arr[i] = abs(arr[i]);

       }

The next element is then selected

       i++;

   }

This sets i to 0

   i = 0;

The following iteration prints the updated content of the array

<em>    while(arr[i]!=0){ </em>

<em>     cout<<arr[i]<<" "; </em>

<em>     i++; </em>

<em> }   </em>

}

See attachment for full program which includes the main

Download cpp
8 0
3 years ago
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