Using the knowledge of computational language in python it is possible to write a code that write (define) a public static method named countup, that takes one int argument and returns no value.
<h3>Writting the code:</h3>
<em>public class </em><em>Main</em>
<em>{</em>
<em>public static void main(</em><em>String</em><em>[] args) {</em>
<em>// testing the method </em><em>countDown </em><em>with values 5, 6, 1</em>
<em>countDown(5);</em>
<em>System.out.println();</em>
<em>countDown(6);</em>
<em>System.out.println();</em>
<em>countDown(2);</em>
<em>System.out.println();</em>
<em>}</em>
<em />
<em>public static void </em><em>countDown</em><em>(int num)</em>
<em>{</em>
<em>for (int i=1 ; i<=num ; i++) // for </em><em>loop </em><em>iterates from 1 to num</em>
<em>{</em>
<em>System.out.print(i+","); // prints num followed by comma ,</em>
<em>}</em>
<em>}</em>
<em>}</em>
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#SPJ1
1. State the problem or question.
2. State the assumptions.
3. Assign digits to represent outcomes.
4. Simulate many repetitions.
5. State conclusions.
If you have any questions, let me know, and I hope this helped! :)
Answer:
The answer is True
Explanation:
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Answer:
Written in Python:
def myfunction():
userinput = input("User input: ")
while(userinput != "end"):
countdown(userinput)
userinput = input("User input: ")
Explanation:
This line defines the function
def myfunction():
This line prompts user for user input
userinput = input("User input: ")
The following while loop checks if userinput is not "end". It continues execution until user input "end"
while(userinput != "end"):
countdown(userinput) If yes, the input is passed to the countdown function for execution
This line prompts user for another user input
userinput = input("User input: ")
<em>Please note the above code segment assumes that countdown() function has already been written and defined</em>
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