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antoniya [11.8K]
3 years ago
8

Write an algebraic expression for the following word expression.

Mathematics
1 answer:
sladkih [1.3K]3 years ago
5 0

Answer:

3m + 13 = 31 I hope this helps you!

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Someone please help me with this
Taya2010 [7]
The answer is clearly C because it just is
5 0
4 years ago
Round 862 liters<br> to the nearest 10<br> liters.
Maksim231197 [3]
The answer is 860 liters. You round down to 860 because it’s closer than 870.
5 0
2 years ago
Use the distance formula to find the area of the rectangle
nasty-shy [4]

Answer:

Therefore Area of Rectangle is 50 unit².

Step-by-step explanation:

Given:

Let the vertices of a Rectangle be

A ( -1 , 7)

B ( 4 , -3)

C ( 0 , -5)

D ( -5 ,5)

To Find:

Area of Rectangle ABCD = ?

Solution:

First we will find the Length and Width of Rectangle by Distance Formula ,

l(AB) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}

Substituting the values we get

l(AB) = \sqrt{((4-(-1))^{2}+(-3-7)^{2} )}

l(AB) = \sqrt{((5)^{2}+(-10)^{2} )}\\l(AB)=\sqrt{125}=5\sqrt{5}\ unit

Similarly for BC we will have,

l(BC) = \sqrt{((0-4)^{2}+(-5-(-3))^{2} )}\\l(BC)=\sqrt{20}=2\sqrt{5}\ unit

Now

Length=AB =5\sqrt{5}\ unit\\Width=BC=2\sqrt{5}\ unit

Now Area of Rectangle is given by

\textrm{Area of Rectangle}=Length\times Width

Substituting the values we get

\textrm{Area of Rectangle ABCD}=5\sqrt{5}\times 2\sqrt{5}=10\times 5=50\ unit^{2}

Therefore Area of Rectangle is 50 unit².

4 0
3 years ago
The letters in the word January are put into a bag drawn randomly what is the probability of an A?
Helga [31]

Answer:

1/49 or 1/42

Step-by-step explanation:

if the letters are put back you would have a 2/7 chance of drawing the letter a each time but if they aren't replaced then you would have a 2/6 chance of getting a

3 0
3 years ago
Y/4+5/9=y/9-5/9<br><br>solve the equation is it a number or does it not have a solution
Paladinen [302]
Google it and you will see the answer
4 0
3 years ago
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