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elixir [45]
3 years ago
9

Let the universe be the set U = {1, 2, 3,..., 10}. Let A = {1, 4, 7, 10}, B = {1, 2, 3, 4, 5}, and C = {2, 4, 6, 8}. List the el

ements of each set.(a) \overline{A} \cap C =\\
|\overline{A} \cap C| =\\
(b) B - \overline{C} = \\
|B - \overline{C}| \\
(c) B \cup A = \\
|B \cup A| =\\
(d) \overline{B} \cap (A - C) = \\
|\overline{B} \cap (A - C)| =\\
(e) (A - B) \cap (B - C) =\\
|(A - B) \cap (B - C)|
Mathematics
1 answer:
Ann [662]3 years ago
7 0

Answer:

Step-by-step explanation:

\overline A\cap  C= {{2,6,8}}\\b. B-\overline {C}=B \cap {C}={{2,4}}\\c.  B \cup A={1,2,3,4,5,7,10}\\d. \overline {B}\cap (A-C)={6,7,8,9,10}\cap {1,7,10}={7,10}\\e. (A-B)\cap (B-C)={7,10} \cap {1,3,5}=\phi

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You have no idea how much it would mean to me and make my day if you helped me with this question ! :)
rodikova [14]
So to do this, you would use the formula: 

Number of favorable outcomes
________________________

Total number of outcomes.


In the first question you are asked: Probability of an even number being spun. We can see that there are 4 even numbers, which is our favorable outcome and that over the number of outcomes, which is 8, would be 4/8 = 0.5 or 50%. Therefore the answer to #1 is 0.5 as a decimal or 50% as a percent. (Do it the way the directions tell you to).

In the second question you are asked the probability to spin a number greater than 3. This does not include 3, so you have 4, 5, 6, 7, and 8. That is 5 numbers. 5 numbers divided by the total number of outcomes is 5/8, which is equal to 0.625, or 62.5%. Therefore the answer to #2 is 0.625 as a decimal or 62.5% as a percent.

The third question asks for the probability that an odd number would be spun. We can see the odd numbers are: 1,3,5,7. This is 4 favorable outcomes divided by 8, the total number of outcomes. 4/8 is equal to 0.5 or 50%. Therefore the answer to #3 is 50% as a percent or 0.5 as decimal.

Hope this helps. Please rate, leave a thanks, and mark a brainliest answer. (Not necessarily mine). Thanks, it really helps!

8 0
3 years ago
I need help finding the values of the last boxes shown in the image.
Bingel [31]

The volume of the region R bounded by the x-axis is: \mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

<h3>What is the volume of the solid revolution on the X-axis?</h3>

The volume of a solid is the degree of space occupied by a solid object. If the axis of revolution is the planar region's border and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

In the graph, the given straight line passes through two points (0,0) and (2,8).

Therefore, the equation of the straight line becomes:

\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}

where:

  • (x₁, y₁) and (x₂, y₂) are two points on the straight line

Thus, from the graph let assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8), we have:

\mathbf{y-0 = \dfrac{8-0}{2-0}(x-0)}

y = 4x

Now, our region bounded by the three lines are:

  • y = 0
  • x = 2
  • y = 4x

Similarly, the change in polar coordinates is:

  • x = rcosθ,
  • y = rsinθ

where;

  • x² + y² = r²  and dA = rdrdθ

Now

  • rsinθ = 0   i.e.  r = 0 or θ = 0
  • rcosθ = 2 i.e.   r  = 2/cosθ
  • rsinθ = 4(rcosθ)  ⇒ tan θ = 4;  θ = tan⁻¹ (4)

  • ⇒ r = 0   to   r = 2/cosθ
  •    θ = 0  to    θ = tan⁻¹ (4)

Then:

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

Learn more about the determining the volume of solids bounded by region R here:

brainly.com/question/14393123

#SPJ1

5 0
2 years ago
75 points. Will give certified if work is shown and the answer is correct.
Svetach [21]
Volume of the first dwarf planet (r₁ = 832 mi):

V_1=\dfrac{4}{3}\cdot\pi\cdot r_1^3=\dfrac{4}{3}\cdot\pi\cdot 832^3=\dfrac{2303721472}{3}\pi\approx7.679\cdot10^8\pi\,\text{mi}^3

Volume of the second dwarf planet (r₂ = 829 mi):

V_2=\dfrac{4}{3}\cdot\pi\cdot r_2^3=\dfrac{4}{3}\cdot\pi\cdot 829^3=\dfrac{2278891156}{3}\pi\approx7.5963\cdot10^8\pi\,\text{mi}^3

So difference between the volumes is:

V_1-V_2\approx7.679\cdot10^8\pi-7.5963\cdot10^8\pi=0.0827\cdot10^8\pi=\boxed{8270000\pi\,\text{mi}^3}

or if we want exact value (we use (a³-b³) = (a-b)(a²+ab+b²) ):

V_1-V_2=\dfrac{4}{3}\cdot\pi\cdot r_1^3-\dfrac{4}{3}\cdot\pi\cdot r_2^3=\dfrac{4}{3}\pi(r_1^3-r_2^3)=\dfrac{4}{3}\pi(832^3-829^3)=\\\\\\=\dfrac{4}{3}\pi(832-829)(832^2+832\cdot829+829^2)=\\\\\\=\dfrac{4}{3}\pi\cdot3(692224+689728+687241)=4\pi\cdot2069193=\boxed{8276772\pi\,\text{mi}^3}
3 0
3 years ago
Are they all correct ? And help with the number 4 please ? Thank you
nirvana33 [79]
Yes they are all correct and for number 4 compare write your own comparison of 2 things like if people like dogs more or cats more
4 0
3 years ago
PLEASE HELP
dimaraw [331]

Answer:

Step-by-step explanation:24,000

4 0
3 years ago
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