Let the universe be the set U = {1, 2, 3,..., 10}. Let A = {1, 4, 7, 10}, B = {1, 2, 3, 4, 5}, and C = {2, 4, 6, 8}. List the el
1 answer:
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The solutions for ‘x’ are 2 and -5
<u>Step-by-step explanation:</u>
Given equation:
Since the base on both sides as ‘12’ are the same, we can write it as
Often, the value of x is easiest to solve by by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.
<u>The Quadratic Formula:</u> For , the values of x which are the solutions of the equation are given by:
Where, a = 1, b = 3 and c = -10
So, the solutions for ‘x’ are
The solutions for ‘x’ are 2 and -5
Answer:
y>5/6
Step-by-step explanation:
5y+3>-7y+13
5y+7y>13-3
12y/12>10/12
y>5/6
This is an inequality, which shows where the variable y does or does not exist
from this we can say
y: (-infinity,5/6) (5/6, infinity]
or, y does not exist from (-infinity,5/6)
and does exist from (5/6, infinity]
