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3 years ago

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Ryan bought a digital camera with a list price of $150 from an online store offering a 5% discount. He needs to pay $5.50 for sh

ipping. What was Ryan's total cost?

1 answer:

zhannawk [14.2K]3 years ago

3 0

I am thinking 150-5% = 142.50 + 5.50 = $148

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X + 3y = -11<br> y = -1<br><br> what does x equal to

KonstantinChe [14]

X+3(-1)= -11
3×(-1)= -3
x+(-3)= -11
x-3= -11
x= -11+3
x= -8

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3 years ago

Read 2 more answers

Monica built a remote-controlled, toy airplane for a science project. To test the plane, she launched it from the top of a build

True [87]

Answer:

[0,50]

Step-by-step explanation:

The function takes from value the distance from the plane to the building, and returns the height of the plane at that point in feets. Assuming that the plane goes always down, it will always be up to the height of the building. Note that the horizontal distance the plane travels at any point is equivalent to the distance of the plane with the building at that point, because the building is perpendicular to the ground. So, at the end of the travel the plane will be 50 feets away from the building. SInce it starts at 0 distance, then the domain of the function is [0,50]

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3 years ago

Pls pls help, thank you <3

Reika [66]

Answer:

(x -1)² +(y -4)² = 25

Step-by-step explanation:

The equation of a circle in standard form is ...

(x -h)² +(y -k)² = r² . . . . . . . circle with center (h, k) and radius r

The graph shows your circle has its center at (1, 4) and its radius is 5. Then the equation is ...

(x -1)² +(y -4)² = 25

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3 years ago

John, Sally, and Natalie would all like to save some money. John decides that it

brilliants [131]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2) $y=100x+300$

Part 3) $\$12,300$

Part 4) $\$2,700$

Part 5) Is a exponential growth function

Part 6) $A=6,000(1.07)^{t}$

Part 7) $\$11,802.91$

Part 8) $\$6,869.40$

Part 9) Is a exponential growth function

Part 10) $A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

Part 11) $\$13,591.41$

Part 12) $\$6,107.01$

Part 13) Natalie has the most money after 10 years

Part 14) Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

y=mx+b

The slope is equal to

$m=\$100\ per\ month$

The y-intercept or initial value is

$b=\$300$

so

$y=100x+300$

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

so

$10\ years=10(12)=120 months$

For x=120 months

substitute in the linear equation

$y=100(120)+300=\$12,300$

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

so

$2\ years=2(12)=24\ months$

For x=24 months

substitute in the linear equation

$y=100(24)+300=\$2,700$

Part 5) What type of exponential model is Sally’s situation?

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$P=\$6,000\\ r=7\%=0.07\\n=1$

substitute in the formula above

$A=6,000(1+\frac{0.07}{1})^{1*t}\\ A=6,000(1.07)^{t}$

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{10}=\$11,802.91$

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{2}=\$6,869.40$

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$P=\$5,000\\r=10\%=0.10$

substitute in the formula above

$A=5,000(e)^{0.10t}$

Applying property of exponents

$A=5,000(1.1052)^{t}$

therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

$A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

$A=5,000(e)^{0.10*10}=\$13,591.41$

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

$A=5,000(e)^{0.10*2}=\$6,107.01$

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

3 0

3 years ago

Sarah invested £12000 in a unit trust 5 years ago, the value of the unit trust increased by 7% per annum for each of the last 3

trasher [3.6K]

Answer:

The current price of the unit trust = £13,831.72

Step-by-step explanation:

Since it increased 7% per annum in last three years and decreased by 3% per annum before that, it implies that the unit trust decreased by 3% per annum for the first 2 years and then increased by 7% per annum for the next 3 years in the total 5 year period

The invested after 2 years = 12,000*(1-0.03)^2 = £11,290.8

This amount then grows by 7% for the next 3 years making it = 11,290.80*(1+0.07)^3 = £13,831.7155 = £13,831.72 (Rounded to 2 decimals)

The current price of the unit trust = £13,831.72 (Rounded to 2 decimals)

6 0

3 years ago