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lesya [120]
3 years ago
9

help? sorry I'm just confused so yeah. please help as much as you can. please and thank you. I can help you in return.

Mathematics
1 answer:
Andrews [41]3 years ago
8 0

First you have to graph the points for y=-4-1. You can make a table and have x and y on either side.

answers:



(if you have any questions please ask)

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Use the rules of exponents to evaluate or simplify. Write without negative exponents.
koban [17]

9514 1404 393

Answer:

  1

Step-by-step explanation:

Any non-zero number to the zero power is 1.

  3.4^0 = 1

4 0
3 years ago
Express 120 as a product of its prime factors.
raketka [301]
By the Fundamental Theorem of Arithmetic, all number can be expressed as a product of prime numbers.

So naturally, lets divide 120 by an easy prime number.
We know that 120 is even, so lets try 2 120/2 = 60 lets keep dividing it by two until it becomes odd or prime 60/2 = 30 30/2 = 15 now lets see, what are some factors of 15?

Well the obvious ones are 3 and 5, both of which are prime. So now we can just count up how many times we divided it by 2
 
120/2 = 60 60/2 = 30 30/2 = 15 and 15 is just 3 x 5, so: <span>
120=(<span>23</span>)×(3)×(5)</span>
or <span><span>
120 = 2 × 2 × 2 × 3 × 5</span></span>
7 0
3 years ago
Read 2 more answers
Let p= x^2-7.
Advocard [28]

Since p = x² - 7, you can substitute/plug in p for x² - 7

So:

(x² - 7)² - 4x² + 28 = 5

(p)² - 4x² + 28 = 5      You can factor out -4 from (-4x² + 28)

p² - 4(x² - 7) = 5        Plug in p

p² - 4p = 5        Subtract 5

p² - 4p - 5 = 0        Your answer is C

8 0
3 years ago
PLEASE HELP ASAP
Vlad [161]

Answer:

  1 : 6 . . . . or 1/6

Step-by-step explanation:

We know 1 foot is 12 inches, so 5 feet is 5·12 = 60 inches. Zachary's scale factor is ...

  drawing size : actual size = 10 inches : 60 inches = 1 : 6

This can also be written as the fraction 1/6.

5 0
3 years ago
Solve each system by substitution. -5x + 3y = 3 and -4x + y = 1
taurus [48]

\left\{\begin{array}{ccc}-5x+3y=3\\-4x+y=1&|\text{add 4x to both sides}\end{array}\right\\\\\left\{\begin{array}{ccc}-5x+3y=3\\y=4x+1&(*)\end{array}\right\\\\\text{Substitute }\ (*)\ \text{to the first equation}\\\\-5x+3(4x+1)=3\qquad\text{use distributive property}\\\\-5x+(3)(4x)+(3)(1)=3\\\\-5x+12x+3=3\qquad\text{subtract 3 from both sides}\\\\7x=0\qquad\text{divide both sides by (-5)}\\\\\boxed{x=0}\\\\\text{Substitute the value of x to}\ (*):\\\\y=4(0)+1\\y=0+1\\\boxed{y=1}\\\\Answer:\ x=0\ and\ y=1.

5 0
3 years ago
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