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ss7ja [257]
4 years ago
8

Law of radicals

Mathematics
1 answer:
andrey2020 [161]4 years ago
6 0

Answer:

1)  \sqrt{x^7}=x^{\frac{7}{2}

2)  \sqrt[3]{y^5}=y^{\frac{5}{3}

3) \sqrt[5]{a^{12}}=a^{\frac{12}{5} }

4) \sqrt[4]{z^{9}}=z^\frac{9}{4}

Step-by-step explanation:

1) \sqrt{x^7}

We know that \sqrt{x}=x^{\frac{1}{2}

So, \sqrt{x^7}=x^{\frac{7}{2}

2) \sqrt[3]{y^5}

We know that \sqrt[3]{x}=x^{\frac{1}{3}

So, \sqrt[3]{y^5}=y^{\frac{5}{3}

3) \sqrt[5]{a^{12}}

We know that \sqrt[5]{x}=x^{\frac{1}{5}

So, \sqrt[5]{a^{12}}=a^{\frac{12}{5} }

4) \sqrt[4]{z^{9}}

We know that \sqrt[4]{x}=x^{\frac{1}{4}

So, \sqrt[4]{z^{9}}=z^\frac{9}{4}

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Write the standard equation for the circle whose center is at ​(6​,2​) and whose radius is 2.
Grace [21]

Answer:

(x - 6)^2 + (y - 2)^2 = 2^2.

Step-by-step explanation:

In general, let (a,\, b) denote the center of a given circle. Let r denote the radius of that circle. The standard equation for that circle would be:

(x - a)^2 + (y - b)^2 = r^2.

The circle in this question is centered at (6,\, 2).  

  • 6 is the x-coordinate of the center of this circle. a = 6.
  • 2 is the y-coordinate of the center of this circle. b = 2.

The radius of this circle is 2. Therefore, r = 2.

Hence, the standard equation for this circle would be:

(x - 6)^2 + (y - 2)^2 = 2^2.

8 0
3 years ago
You download a video game to your computer. You have a 60 minute free trial of the game. It takes 5 minutes to set up the game a
den301095 [7]

Answer:

You can play 7 full levels for free.

Step-by-step explanation:

60-5= 55 minutes left to play

55/7=7.857

So.... 7 full levels for free

4 0
3 years ago
A2+b2 = C2solve for a
lesantik [10]
a^2+b*2=c^2 

a^2+2b=c^2

  \text{Regroup terms} 

a^2=c^2-2b
  \text{Subtract 2b from both sides} 

a=\pm \sqrt{c^2-2b}  \text{Take the square root of both sides}

3 0
3 years ago
A bowling alley charges $2.50 per game plus $4 to rent shoes. A second bowling alley charges $4 per game plus $1 to rent shoes.
adelina 88 [10]

Answer:

The person would have to play 2 games for the two bowling alleys to cost the same amount

Step-by-step explanation:

Assume that the number of games that makes the two costs equal is x

∵ A bowling alley charges $2.50 per game plus $4 to rent shoes

∵ The number of games is x

∴ The cost = 2.50x + 4

∵ A second bowling alley charges $4 per game plus $1 to rent shoes

∵ The number of games is x

∴ The cost = 4x + 1

∵ They have the same cost

→ Equate the 2 expressions above

∴ 4x + 1 = 2.50x + 4

→ Subtract 2.50x from both sides

∵ 4x - 2.50x + 1 = 2.50x - 2.50x + 4

∴ 1.50x + 1 = 4

→ Subtract 1 from both sides

∵ 1.50x + 1 - 1 = 4 - 1

∴ 1.50x = 3

→ Divide both sides by 1.50

∴ x = 2

∴ The person would have to play 2 games for the two bowling alleys to

   cost the same amount

7 0
3 years ago
WILL MARK YOU BRAINLIEST ANSWER WHAT YOU CAN PLS
maks197457 [2]

Answer:

1.

T mBAC = mB'A'C'

F 2mABC = mA'B'C'

F BC = 2B'C'

T 2XA = XA'

2

D'(-2/3; -1)

E'(-1;1)

F'(1;1)

G'(1;-1)

3

the centre is L(0;-2)

the scale factor is 4

length J'K' = 4JK

the measure of L is equal the measure of L'

<u>the</u><u> </u><u>table</u><u>:</u>

K(4;2) 4 4 16 16 0+16 -2+16 K'(16;14)

8 0
3 years ago
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