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kodGreya [7K]
2 years ago
7

Charlotte owns two entertainment websites. Here are some details about those websites for one entire month:

Mathematics
2 answers:
sattari [20]2 years ago
7 0

Answer:

Part 1:

Revenue divided by number of posts

Revenue divided by total number of words

Part 2:

No. The definitions have opposite results.

Step-by-step explanation:

When you divide revenue by total number of words remember to do words*posts to get total.

Example: $30000/100*110 = 2.72

DedPeter [7]2 years ago
5 0
It is d and b I believe
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Hazel bought a bread toaster from an online company the original price of the Bread toaster Was $50 she received a 20% discount
alexgriva [62]
C. 20% minus 10% is 10%.
3 0
3 years ago
Drag the tiles to the boxes to form correct pairs. Match each function to the equation of the tangent line to its graph at x = 2
Ede4ka [16]

Step-by-step explanation:

the picture includes the answer and work

I plugged in 2 for x

the equations that got the same answer, I put together

3 0
3 years ago
Maymona book club is ordering new novels, She knows that the total cost of 6 books is $90, and 10 books cost $150. Write an equa
aleksandr82 [10.1K]

Answer:

Y=15x

Step-by-step explanation:

<h2>Okay so let's approach this problem!</h2><h2 />

X is books and Y is total cost

Let's find the slope!

Y2-Y1/ X2-X1

Just replace

\frac{150 - 90}{10 - 6}

\frac{60}{4}  = 15

The slope is 15

y = 15x + b

Now replace x and y with coordinates and solve

150 = 15(10) + b \\ 150 = 150 + b \\  - 150 \\ 0 = b

The final equation:

y = 15x

That's it! If you have any questions please ask! Brainliest Appreciated.

6 0
2 years ago
The crew on a fishing boat caught 4 fish that weighed a total of 1,092 pound. The tarpon weighed twice as much as the amberjack
Savatey [412]

ddddd

Let T be the weight of Tarpon

Let A be the weight of amberjack

Let W be the weight of white marlin

Let TU be the weight of Tuna

The crew on a fishing boat caught 4 fish that weighed a total of 1,092 pound.

Total weight = 1092

T + A + W + TU = 1092

The tarpon weighed twice as much as the amberjack

T= 2 A

  the white marlin weighed twice as much as the tarpon.

W = 2 T

We know T is 2A  so W = 2(2A) = 4 A, W = 4A

The weight of the tuna was 5 times the weight of the Amber jack.

TU = 5A

T = 2A  , W = 4A , TU = 5A

Replace it in our equation

T + A + W + TU = 1092

2A + A + 4A + 5A = 1092

12A = 1092

Divide both sides by 12

A = 91

the weight of amberjack = 91 pounds

the weight of white marlin = 4A = 4(91) = 364 pounds

the weight of Tarpon = 2A = 2(91) = 182 pounds

the weight of Tuna= 5A = 5(91)=455 pounds

7 0
2 years ago
Implicit differentiation Please help
Anvisha [2.4K]

Answer:

y''(-1) =8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Factoring

<u>Calculus</u>

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Product Rule: \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Chain Rule: \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Quotient Rule: \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Step-by-step explanation:

<u>Step 1: Define</u>

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

<u>Step 2: Differentiate Pt. 1</u>

<em>Find 1st Derivative</em>

  1. Implicit Differentiation [Product Rule/Basic Power Rule]:                            -y - xy' - 2y' = 0
  2. [Algebra] Isolate <em>y'</em> terms:                                                                               -xy' - 2y' = y
  3. [Algebra] Factor <em>y'</em>:                                                                                       y'(-x - 2) = y
  4. [Algebra] Isolate <em>y'</em>:                                                                                         y' = \frac{y}{-x-2}
  5. [Algebra] Rewrite:                                                                                           y' = \frac{-y}{x+2}

<u>Step 3: Find </u><em><u>y</u></em>

  1. Define equation:                    -xy - 2y = -4
  2. Factor <em>y</em>:                                 y(-x - 2) = -4
  3. Isolate <em>y</em>:                                 y = \frac{-4}{-x-2}
  4. Simplify:                                 y = \frac{4}{x+2}

<u>Step 4: Rewrite 1st Derivative</u>

  1. [Algebra] Substitute in <em>y</em>:                                                                               y' = \frac{-\frac{4}{x+2} }{x+2}
  2. [Algebra] Simplify:                                                                                         y' = \frac{-4}{(x+2)^2}

<u>Step 5: Differentiate Pt. 2</u>

<em>Find 2nd Derivative</em>

  1. Differentiate [Quotient Rule/Basic Power Rule]:                                          y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}
  2. [Derivative] Simplify:                                                                                      y'' = \frac{8}{(x+2)^3}

<u>Step 6: Find Slope at Given Point</u>

  1. [Algebra] Substitute in <em>x</em>:                                                                               y''(-1) = \frac{8}{(-1+2)^3}
  2. [Algebra] Evaluate:                                                                                       y''(-1) =8
6 0
3 years ago
Read 2 more answers
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