1)144 ft
2)6,600 cm
3)1,008 m
4)9,720m
1 foot = 12 inches
(1 foot)³ = (12 inches)³
12³ = 1,728 in³
To change 10 cubic feet into cubic inches
10 ft³ * 1728 in³/ft³ = 17,280 in³ Choice C. Multiply by 1,728
Answer:
it let me now!!
Step-by-step explanation:
so i cant put an answer for some reason but here it is: when dividing fractions you would need to multiply to solve. The easyist way to do so from the ways i learned is keep change flip. so keep: 2/3 change a divide to a multiplication simbol and flip 1/4 to 4/1 so your left with G: 2/3 x 4/1
hope that helps btw if you need me to explain more let me know whats confusing you so i can help!!
Answer:
740 or 990
Step-by-step explanation:
It just depends on the height. I don't know if it is 10 or 15. If the height is 15 then 990. If the height is 10 then 740. :)
This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.
There aren't any parallel lines involved in the above described construction, so I'll skip the first one.
2. Why do the circles have to be congruent ...
The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.
3. ... circles of different sizes ...
[We just answered that. Let's do it again.]
Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.
4. ... construct the perpendicular bisector ... a different way?
Maybe what I first described is different; there are no parallel lines.
