WILL GIVE BRAINLIEST!

Mary wants to fill in a cylinder vase. At the flower store they told her that the vase should be filled for the flowers to last

frutty [35]

For the problem, we are asked t o calculate the volume of the cylindrical vase and it will represent the amount of water that Mary should pour. For a cylinder, the volume is calculated as follows:

V = πr²l
V = π(3)²(8)
<span>V = 226.19 in³ water needed</span>

8 0

3 years ago

A rocket is launched into the air and follows the path, h (t) = -3 * t^2 + 12 * t

DanielleElmas [232]

check the picture below.

so, the rocket will come back to the ground when h(t) = 0, thus

$\bf h(t)=-3t^2+12t\implies \stackrel{h(t)}{0}=-3t^2+12t\implies 0=-3t(t-4)\\\\[-0.35em]~\dotfill\\\\0=-3t\implies 0=t\impliedby \textit{0 seconds when it took off from the ground}\\\\[-0.35em]~\dotfill\\\\0=t-4\implies 4=t\impliedby \textit{4 seconds later, it came back down}$

8 0

4 years ago

What are the coordinates of the midpoint of the line segment with endpoints 2,-5) and (8,3)

ELEN [110]

Answer:

(5, -1)

Step-by-step explanation:

Add the x-coordinates and divide by 2.

Add the y-coordinates and divide by 2.

x-coordinate of midpoint: (2 + 8)/2 = 10/2 = 5

y-coordinate of midpoint: (-5 + 3)/2 = -2/2 = -1

Midpoint: (5, -1)

6 0

3 years ago

Small scooters cost £80 and large scooters cost £130. A school buys few scooters for the playground for £1000. How many of the s

Sonbull [250]

Answer:

Small scooters = 6

Large scooters = 4

Step-by-step explanation:

Let S represents small scooter and L represents large scooter

The cost of a small scooter is £80

Mathematically, the cost of S number of small scooters is

80S

The cost of a large scooter is £130

Mathematically, the cost of L number of large scooters is

130L

The total amount spent on both scooters is £1000

Mathematically,

80S + 130L = 1000

So we have 2 unknowns and only 1 equation. Therefore, we have use trial and error method .

Trial and Error Method:

80S + 130L = 1000

80S = 1000 - 130L

S = (1000 - 130L)/80

Let’s suppose they bought 1 large scooter

S = (1000 - 130(1))/80

S = 10.875

Number of scooters cannot be in fraction so 1 doesn’t work

Let’s suppose they bought 2 large scooter s

S = (1000 - 130(2))/80

S = 9.25

Number of scooters cannot be in fraction so 2 doesn’t work

Let’s suppose they bought 3 large scooter s

S = (1000 - 130(3))/80

S = 7.625

Number of scooters cannot be in fraction so 3 doesn’t work

Let’s suppose they bought 4 large scooters

S = (1000 - 130(4))/80

S = 6

So that means they bought 6 small scooters and 4 large scooters.

Similarly, other combinations for scooters don’t work since they yield either fractional value or negative value which cannot be correct.

Therefore, the only possible combination of small and large scooters is

6 Small scooters

4 Large scooters

Verification:

80S + 130L = 1000

80(6) + 130(4) = 1000

480 + 520 = 1000

1000 = 1000 (satisfied)

8 0

4 years ago

I'm blanking on how to do this, I learned it so long ago, any help would be greatly appreciated. More interested on how to do it

anyanavicka [17]

Answer:

$\dfrac{16 y^{22}}{x^{10}z^{10}}$

Step-by-step explanation:

Given expression is ,

$\sf\longrightarrow \bigg(\dfrac{2x^3y^{-5}z^8}{8x^{-2}y^6z^3}\bigg)^{-2}$

This would be simplified using the law of exponents , some of which I will use here are ,

$(an)^m = a^m n^m$
$\dfrac{a^m}{a^n}=a^{m-n}$

$a^m a^n = a^{m+n}$
$a^{-n} = \dfrac{1}{a^n}$

Using the above laws ,

$\sf \longrightarrow \bigg[ \dfrac{2}{8} \bigg(\dfrac{x^3}{x^{-2}}\bigg)\bigg(\dfrac{y^{-5}}{y^6}\bigg)\bigg(\dfrac{z^8}{z^3}\bigg) \bigg]^{-2}$

Using the second law mentioned above , we have,

$\sf \longrightarrow \bigg[ \dfrac{1}{4}(x^{3+2})(y^{-5-6})(z^{8-3})\bigg]^{-2}$

Simplify ,

$\sf \longrightarrow \bigg[\dfrac{1}{4} x^5y^{-11}z^5\bigg]^{-2}$

Using the first law mentioned above , we have,

$\sf \longrightarrow \bigg[ \dfrac{1}{4^{-2}} x^{5(-2)} y^{-11(-2)} z^{5(-2)}\bigg]$

Simplify,

$\sf \longrightarrow 4^2x^{-10}y^{22} z^{-10}$

Finally using the fourth law mentioned above , we have ,

$\sf \longrightarrow \boxed{\bf \dfrac{16 y^{22}}{x^{10}z^{10}}}$

<h3>Option K is the correct answer.</h3>

4 0

2 years ago