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sleet_krkn [62]
3 years ago
8

How many weeks will it take him to afford a car worth £1932

Mathematics
1 answer:
andreev551 [17]3 years ago
4 0
7 hours a day
7 x €9.20 = €64.4 per day

6 days a week
€64.4 x 6 = €386.4 per week

Will:Mum = 5:2

386.4 / 7 = 55.2

Will: 55.2 x 5 = 276

After shares his wages, Will makes $276 a week

<span>1932 / 276 = 7 weeks</span>

<span>
</span>

<span>answer</span>

<span>7 weeks</span>

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If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

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2 years ago
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MariettaO [177]
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If K is the midpoint of JL, JK = 9x -1 and KL = 2x +27, find JL
Liula [17]

Answer:

JL = 70

Step-by-step explanation:

Since K is the midpoint of JL then JK = KL and

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solve for x using JK = KL

9x - 1 = 2x + 27 ( subtract 2x from both sides )

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JL = 11x + 26 = (11 × 4 ) + 26 = 44 + 26 = 70


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