The woman is 61.5 inches tall.
This question is essentially asking for how many standard deviations the woman's height is away from the mean men's height.
Only 1 in 400 (or 0.25%) of men is shorter than our picky homegirl. If you think of a normal distribution of men's heights, this is the extreme left tail end. As a rule of thumb, +/- 3 standard deviations around the mean captures 99.5% of a population, leaving 0.5% outside of the interval (so, only 0.25% on each end). So we know that our girl refuses to marry anyone lower than -3 standard deviations from the mean.
All that's left is to plug in the given mean and SD:
69 -3(2.5) = 61.5 inches
Answer:
The length of QR to the nearest tenth of a foot is 287.28 feet.
Step-by-step explanation:
Let a right angled Triangle QRS have base SQ, perpendicular RS and Hypotenuse QR.
∠S = 90°
∠Q = 17°
Perpendicular = 84 ft
We know that for a right angle triangle
SinΘ = perpendicular/Hypotenuse
Sin ∠Q = 84/QR
QR = 84/sin(17°)
QR = 84/0.2924
QR = 287.2777
QR = 287.28 feet
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5) y=-5/2x-5
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