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blagie [28]
3 years ago
12

Please help!! i have no idea!

Mathematics
2 answers:
Gemiola [76]3 years ago
7 0

Answer:

θ = 60.34

Step-by-step explanation:

\frac{\left(12.8\cdot \:sin\left(90\right)\right)}{sin\left(52.3\right)} = 16.177

\frac{\left(16.177\cdot \:sin\left(90\right)\right)}{18.6} =  θ = .869

arcsin\left(.869\right) = 60.34

Mariulka [41]3 years ago
5 0

Answer:

60.4°

Step-by-step explanation:

There are two right triangles.

One right triangle (on the left side) has an acute angle measuring 52.3°.

Its opposite leg measures 12.8 cm.

We can find the length of its hypotenuse, x.

sin 52.3° = opp/hyp

sin 52.3° = 12.8 cm/x

x * sin 52.3° = 12.8 cm

x = 12.8 cm/sin 52.3°

x = 16.2 cm

Now we use the hypotenuse of the left side triangle which is a leg of the right side triangle.

For the right side triangle, we are looking for angle Θ. We know the opposite leg, 16.2 cm and the hypotenuse, 18.6 cm.

sin Θ = opp/hyp

sin Θ = 16.2/18.6

sin Θ = 0.8698

Θ = sin^-1 0.8698

Θ = 60.4°

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Answer: The answer is (C) 324 cubic cm.


Step-by-step explanation: As given in the question, given a solid oblique pyramid with a regular hexagonal base and area 54√3 cm². Also, the edge length of the base is 6cm and ∠BAC = 60°.

We are to find the volume of the pyramid.

The formula for finding the volume of a pyramid is given by

V=\dfrac{1}{3}b\times h,

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Here, b = 54√3 cm², h = ?

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\dfrac{\textup{BC}}{\textup{AC}}=\tan 60^\circ\\\\\Rightarrow \dfrac{h}{6}=\sqrt 3\\\\\Rightarrow h=6\sqrt 3.

Therefore, the volume of the pyramid is

V=\dfrac{1}{3}b\times h=\dfrac{1}{3}\times 54\sqrt 3\times 6\sqrt 3=324.

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15 is what percent of 90?​
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