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morpeh [17]
4 years ago
14

A polling agency conducted a survey by selecting 100 random samples, each consisting of 1,200 United States citizens. The citize

ns in each sample were asked whether they were optimistic about the economy. For each sample, the polling agency created a 95 percent confidence interval for the proportion of all United States citizens who were optimistic about the economy. Which of the following statements is the best interpretation 5. A e 95 percent confidence level? (A) with 100 confidence intervals, we can be95% co nfident that the sample proportion of citizens of the (B) We would expect about 95 of the 100 confidence intervals to contain the proportion of all citizens of the (C) We would expect about 5 of the 100 confidence intervals to not contain the sample proportion of citizens of (D) Of the 100 confidence intervals, 95 of the intervals will be identical because they were constructed from (E) The probability is 0.95 that 100 confidence intervals will yield the same information about the sample United States who are optimistic about the economy
Mathematics
1 answer:
inn [45]4 years ago
5 0

Answer:

Correct option (B).

Step-by-step explanation:

A 95% confidence interval for a population parameter implies that there is 0.95 probability that the population parameter is contained in that interval.

Or, if 100, 95% confidence intervals are created then 95 of those intervals would contain the population parameter with probability 0.95.

In this question the 95% confidence interval was created for population proportion of all United States citizens who were optimistic about the economy.

Then this 95% confidence interval implies that if 100 such confidence intervals were created then 95 of those would consist of the true proportion of US citizens who were optimistic about the economy..

Thus, the correct option is (B).

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Estimate 3458092=3500000~; 57=60~.
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The winner of an election is voted for by the majority of people. If there are two things being voted for, veggie pizza and chicken, and pizza earns 36% of the vote, then chicken must earn 64% of the vote because 36 and 64 add to 100.

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A bank is reviewing its risk management policies with regards to mortgages. To minimize the risk of lending, the bank wants to c
agasfer [191]

1. μ = 306,500

2.σ = 24,500

3. n = 150

4. μ_x = $306,500

5. σ_x = $2000

<h3>What is Standard deviation?</h3>

The standard deviation serves as a gauge for the degree of variation or dispersion among a group of numbers. While a high standard deviation suggests that the values are dispersed throughout a wider range, a low standard deviation suggests that the values tend to be close to the mean of the collection.

With a standard deviation of $24,500 and an average mortgage debt of $306,500, Americans have a median mortgage debt.

<h3>According to the given information:</h3>

The population's average is

μ = 306,500

Standard deviation for the general population is

σ = 24500

Imagine 150 Americans are chosen at random for the sample.

n= 150

The sample mean is roughly normally distributed as a result of the high sample size, which is supported by the central limit theorem.

The population mean and sample mean would be the same,

μ_n = μ =306,500

Here is how to calculate the sample standard deviation:

\sigma_{x}=\frac{\sigma}{\sqrt{n}}

the sample size is n, and is the population standard deviation.

\begin{aligned}&\sigma_{x}=\frac{24,500}{\sqrt{150}} \\&\sigma_{x}=\$ 2,000\end{aligned}

The necessary conditions are thus:

1. μ = 306,500

2.σ = 24,500

3. n = 150

4. μ_x = $306,500

5. σ_x = $2000

To know more about Standard deviation visit:

brainly.com/question/16965372

#SPJ4

I understand that the question you are looking for is :

A bank is reviewing its risk management policies with regards to mortgages. To minimize the risk of lending, the bank wants to compare the typical mortgage owed by their clients against other homebuyers. The average mortgage owed by Americans is $306,500, with a standard deviation of $24,500. Suppose a random sample of 150 Americans is selected. Identify each of the following, rounding your answers to the nearest cent when appropriate:

1.1.  $mu=?\\2. $sigma=?\\3. $=n=$\\4. $mu_{overlinex}=$x=?\\5. $sigma_{overlinex}=$x=?

4 0
2 years ago
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Answer:

Relation 1,2,and 4 are functions, but relation 3 not is a function.

Step-by-step explanation:

function 1 input, no function with the same input like m in relation 3.

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Lisa's cut will be represented by the equation y = 1/4x + 4


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