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2 years ago

What is the rate of change?? please i need asap

Mathematics

1 answer:

Mariana [72]2 years ago

7 0

Answer: Rate of change is used to mathematically describe the percentage change in value over a defined period of time, and it represents the momentum of a variable. ... Subtract one and multiply the resulting number by 100 to give it a percentage representation.

Step-by-step explanation:

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the 41st term of the arithmetic sequence is -539 and the 54th term is -708. Find the value of the 80th term

yulyashka [42]

Answer:

$a _{n} = a _{1} + (n - 1)d \\ a _{41} = - 534 \\ a _{54} = - 708 \\ a _{41} = a _{1} + (41 - 1)d = - 534 \\ a _{1} + 40d = - 534 \: \: ...(1)\\ a _{54} = a _{1} + (54 - 1)d =- 708 \\ a _{1} + 53d = - 708 \: \: ...(2)$

Try to solve the similtanious equation to find the first term and the common difference, then use that information to figure out the 80th term... Update me if you need further help ...

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2 years ago

Need help ^^^^^^^^^^

NeX [460]

The answer is B. 2y+3
this is proven by multiplying the divisor of the original question and the solution
$(y-5)(2y+3)
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4 0

3 years ago

A bacteria colony increases in size at a rate of 4.0581e1.6t bacteria per hour. If the initial population is 36 bacteria, find t

Harrizon [31]

Answer:

1560

Step-by-step explanation:

The rate of Increase of the population (P) of the bacteria is given as:

$\frac{dP}{dt} =4.058e^{1.6t}$

$dP =4.058e^{1.6t}}dt\\Taking\: Integrals\\\int dP =4.058 \int e^{1.6t}dt\\P(t)=\frac{4.058}{1.6} (e^{1.6t} +K)\\P(t)=2.53625 (e^{1.6t} +K)$

Where k is a constant of Integration.

At t=0, P(t)=36

$36=2.53625 (e^{1.6*0} +K)\\36=2.53625 (e^{0} +K)\\36=2.53625 (1 +K)\\36=2.53625 +2.53625K\\K=13.19$

Therefore:

$P(t)=2.53625 (e^{1.6t} +13.19)\\At \: t=4\\P(4)=2.53625 (e^{1.6*4} +13.19)\\=1559.88\\P(4)=1560$

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3 years ago

explain why multiplying the numerator and denominator of a fraction by the same number results in an equivalent fraction

Tomtit [17]

Think: You're treating the numerator and the denom. in precisely the same way. In doing so you are NOT changing the value of the fraction, only the appearance.

Example: start with 2/3. Mult num. and den. both by 7: 14/21.

2/3 and 14/21 result in precisely the same decimal fraction, showing that the latter set of fractions is equivalent to the former set.

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3 years ago

Plot 9/10 and 1 2/5 on the number line below

HACTEHA [7]

First one is 9/10 second is 1 2/5

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2 years ago