Probably 2561 but since area equal r^2 I thought it would be 3217
Option 2 => 6.4^2
Because area of a square = side *side or side^2
Hope this helps u..!!!
The second option. A is 36 and B is 20. FD is half of AC, so 18*2 is 36. FB is half of EC, so it’s 20.
∆BOC is equilateral, since both OC and OB are radii of the circle with length 4 cm. Then the angle subtended by the minor arc BC has measure 60°. (Note that OA is also a radius.) AB is a diameter of the circle, so the arc AB subtends an angle measuring 180°. This means the minor arc AC measures 120°.
Since ∆BOC is equilateral, its area is √3/4 (4 cm)² = 4√3 cm². The area of the sector containing ∆BOC is 60/360 = 1/6 the total area of the circle, or π/6 (4 cm)² = 8π/3 cm². Then the area of the shaded segment adjacent to ∆BOC is (8π/3 - 4√3) cm².
∆AOC is isosceles, with vertex angle measuring 120°, so the other two angles measure (180° - 120°)/2 = 30°. Using trigonometry, we find

where
is the length of the altitude originating from vertex O, and so

where
is the length of the base AC. Hence the area of ∆AOC is 1/2 (2 cm) (4√3 cm) = 4√3 cm². The area of the sector containing ∆AOC is 120/360 = 1/3 of the total area of the circle, or π/3 (4 cm)² = 16π/3 cm². Then the area of the other shaded segment is (16π/3 - 4√3) cm².
So, the total area of the shaded region is
(8π/3 - 4√3) + (16π/3 - 4√3) = (8π - 8√3) cm²
The formula in solving the length of an arc is shown below:
Length of an Arc = 2pi*r (central angle/360°)
Central angle = 54pi * (180°/pi)
r = 34 cm
Solving for an arc length"
Arc length = 2*3.14*34((54*180)/360)
Arc length = 5,765.04 cm
The answer is 5,765.04 cm.