Part 1:
6(x-5) = 5(x+5) (x = 55)
4y + 2 (-3 + 2y) = 1-y (x = 7/9)
Part 2:
4(a-6) = 8a - (4a-24) (No Solution)
4(2x-8) = 8(x-8) (No Solution)
2(3x-3) = -6x-6 (Identity (x = 0))
Answer:
4,6,8
Step-by-step explanation:
Let x = 1st even integer
x+2 =2nd even integer
x+4 =3nd even integer
x+ x+2 + x+4 = 18
Combine like terms
3x+6 = 18
Subtract 6 from each side
3x+6-6=18-6
3x= 12
Divide by 3
3x/3 =12/3
x = 4
x+2 = 6
x+4 = 8
So, the definite integral 
Given that
We find
<h3>Definite integrals </h3>
Definite integrals are integral values that are obtained by integrating a function between two values.
So, 
So, ![\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E1_0%20%7B%284%20-%206x%5E%7B2%7D%20%29%7D%20%5C%2C%20dx%20%3D%20%5Cint%5Climits%5E1_0%20%7B4%7D%20%5C%2C%20dx%20-%20%5Cint%5Climits%5E1_0%20%7B6x%5E%7B2%7D%20%7D%20%5C%2C%20dx%20%5C%5C%3D%20%204%5Bx%5D%5E%7B1%7D_%7B0%7D%20%20%20%20-%20%5Cint%5Climits%5E1_0%20%7B6x%5E%7B2%7D%20%7D%20%5C%2C%20dx%20%5C%5C%3D%20%204%5Bx%5D%5E%7B1%7D_%7B0%7D%20%20%20%20-%206%5Cint%5Climits%5E1_0%20%7Bx%5E%7B2%7D%20%7D%20%5C%2C%20dx%20%5C%5C%3D%204%5B1%20-%200%5D%20%20%20%20-%206%5Cint%5Climits%5E1_0%20%7Bx%5E%7B2%7D%20%7D%20%5C%2C%20dx%5C%5C%3D%204%5B1%5D%20%20%20%20-%206%5Cint%5Climits%5E1_0%20%7Bx%5E%7B2%7D%20%7D%20%5C%2C%20dx%5C%5C%3D%204%20%20%20%20-%206%5Cint%5Climits%5E1_0%20%7Bx%5E%7B2%7D%20%7D%20%5C%2C%20dx)
Since
,
Substituting this into the equation the equation, we have
So,
Learn more about definite integrals here:
brainly.com/question/17074932
Answer:
A
Step-by-step explanation:
its hard to explain but pretty much if you didn't know the ^x+1 is the x intercept except when its graphed its no marked at (1,0) its mark ate (-1,0) because it always takes the inverse
if you go over to the right 3 then your adding 3 to the x intercept or subtracting 3 from ^x+1 so it would be ^x-2
the y intercept part is easy all you have to do is subtract 2 from the y intercept so it would be +2
hope this helps :D
