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Nuetrik [128]
3 years ago
8

b is the midpoint of AC. a has coordinates (9.11), and B has coordinates (-10,5). find the coordinates of c.

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
3 0
C=(-10;5). If you want an explanation I would be happy to explain it
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Question is attached
TiliK225 [7]

Answer:

The relation passes the vertical line test.

Step-by-step explanation:

When you graph the points, a vertical line can be drawn through them without hitting another point.

If this answer is correct, please make me Brainliest!

6 0
3 years ago
Jack covers his ears when he hears a loud sound. Which statement is correct?
Gre4nikov [31]

Answer:

correct answer is 3

Step-by-step explanation:

8 0
3 years ago
The ratio of money in Terry's bank account to Faye's bank account was 3:5.
inn [45]

Answer:

<em>Terry had £780 initially and Faye had £1300</em>

Step-by-step explanation:

<u>System of Equations</u>

We'll call the following variables:

x = Terry's balance in his bank account

y = Faye's balance in her bank account

The initial relation between them is:

\frac{x}{y}=\frac{3}{5}

Cross-multiplying:

5x = 3y        [1]

If Terry put £220 in his account he had x+220 and if Faye withdrew £300 from her account, she had y-300. Both quantities are equal, thus

x + 220 = y - 300

Subtracting 220:

x = y - 520         [2]

Substituting in [1]

5(y - 520) = 3y

Multiplying:

5y - 2600 = 3y

Adding 2600 and subtracting 3y:

2y = 2600

Dividing by 2:

y = 1300

From [2]:

x = 1300 - 520

x = 780

Terry had £780 initially and Faye had £1300

7 0
3 years ago
Polygon ABCD is dilated, rotated, and translated to form polygon A′B′C′D′. The endpoints of AB are at (0, -7) and (8, 8), and th
Anton [14]

Rotation and translation are rigid transformations, they don't change figure sizes. Dilation change figure sizes increasing or decreasing them by scale factor.

First, find AB and A'B' by the formula:

AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}= \sqrt{(8-0)^2+(8-(-7))^2}=\sqrt{8^2+15^2}=\sqrt{64+225}=\sqrt{289}=17,\\ \\A'B'=\sqrt{(x_{B'}-x_{A'})^2+(y_{B'}-y_{A'})^2}= \sqrt{(2-6)^2+(1.5-(-6))^2}=\sqrt{4^2+7.5^2}=\sqrt{16+56.25}=\sqrt{72.25}=8.5.

As you can see AB=2A'B'. This means that the segment AB was decreased twice to form segment A'B'. Then the scale factor is 1/2.

8 0
3 years ago
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