Question

Use a special-product rule to factor the perfect-square trinomial. y^4 - 6y^2 + 9

Answer 1

Answer:

The factorization of the perfect-square trinomial is: $(y^2 - 3)^2$

Step-by-step explanation:

These two factorizations involve perfect-square trinomials.

$(x + y)^2 = x^2 + 2xy + y^2$

$(x - y)^2 = x^2 - 2xy + y^2$

In this question, we use the second. So

$y^4 - 6y^2 + 9 = (y^2 - 3)^2$

The factorization of the perfect-square trinomial is: $(y^2 - 3)^2$