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3 years ago

How do I factor out the coefficient of the variable such as 1/3b -1/3?

Mathematics

2 answers:

marshall27 [118]3 years ago

7 0

It's very easy. We have a common multiple, in this case 1/3 and we need to factor it:

$\frac{1}{3}b- \frac{1}{3} = \frac{1}{3}(b-1)$

Notice that if you distribute the 1/3 in again, you will end up with the same thing. So that's your answer. Hope I could help! :)

Nutka1998 [239]3 years ago

5 0

I think it is factored out like this:
1/3(b-1)

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I beg for someone. I need a maximum, minimum, domain, and range of polynomial:

elena-s [515]

Answer:

domain: all real numbers, (-∞, ∞)
range: all real numbers, (-∞, ∞)
maximum: +∞
minimum: -∞

Step-by-step explanation:

The function is an odd-degree polynomial. The domain and range of any odd-degree polynomial is (-∞, +∞). It has no finite maximum or minimum.

There are 3 local maxima, and 3 local minima. The ones that are non-zero are irrational. Those are about -150.018, -580.455, and 578.545. If you're seriously expected to solve for these values, no doubt you have been given a method for doing so. Use that method.

These local extreme values are reported by the Desmos on-line graphing calculator.

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3 years ago

Which of the following equations is of a parabola with a vertex at (3, 0)?

bixtya [17]

Answer:

D. y = (x - 3)²

Step-by-step explanation:

The parabola formula in vertex form is:

y = a(x - h)² + k

where the vertex is located at (h, k). Replacing with vertex (3, 0) we get:

y = a(x - 3)² + 0

y = a(x - 3)²

In all possible options the leading coefficient a is equal to one. Therefore:

y = (x - 3)²

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2 years ago

jayson buys a car and pays by installments, each installments is $567 per month. after 48 months, jayson owes $1250. what was th

KIM [24]

Okay so like, all you've gotta do is multiply 567 by 48 & add 1250. Leaving you with the answer of 28,466

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3 years ago

An economy pack of highlighters contains 12 yellow, 6 blue, 4 green, and 3 orange highlighters. An experiment consists of random

Serhud [2]

Answer:

The probability of choosing a blue or yellow highlighter when one yellow highlighter is picked is 17/25.

Step-by-step explanation:

Here, according to the question:

Total number of yellow highlighters = 12

Total number of blue highlighters = 6

Total number of green highlighters = 4

Total number of orange highlighters = 3

So, the total number of highlighters = 12 + 6 + 4 + 3 = 25

Let E1 : Event of selecting a yellow highlighter.

P(E1) = $\frac{\textrm{Total number of yellow highlighters}}{\textrm{Total Highlighters}}$ = $\frac{12}{25}$

Let E2 : Event of selecting blue or yellow highlighter ONCE yellow highlighter is selected.

So, the total yellow highlighters left after selecting one = 12 -1 = 11

Also, the number of blue highlighter = 6

So, the TOTAL FAVORABLE options to E2 = 6+ 11 = 17

P(E2) =

$\frac{\textrm{Total number of yellow + Blue highlighters}}{\textrm{Total Highlighters}}$ = $\frac{17}{25}$

Hence, the probability that a blue or yellow highlighter is selected given that a yellow highlighter is selected is 17/25.

7 0

3 years ago

Someone help me

Aneli [31]

Answer:

see the explanation

Step-by-step explanation:

we know that

The circumference of a circle is equal to

$C=\pi D$

where

D is the diameter

In this problem we have

$C=2.88\ in$

$\pi=3$

substitute and solve for D

$2.88=(3)D$

$D=2.88/3$

$D=0.96\ in$

we know that

The length of the row of quarters is equal to multiply the diameter of the quarter by the number of quarters in the row

For 4 quarters in the row, the length is equal to --> $0.96(3)=3.84\ in$

For 6 quarters in the row, the length is equal to --> $0.96(6)=5.76\ in$

For 12 quarters in the row, the length is equal to -> $0.96(12)=11.52\ in$

6 0

3 years ago