Answer:
(B) Segments MA and MB
Step-by-step explanation:
The tangent to the circle at a point is perpendicular to the radius of the circle drawn to the point of tangency.
Tangent at a point is unique.
Since there can be no two tangents at a point on circle, the options (b) and (c) are ruled out.
Now, if OA is perpendicular to MA, MA is the tangent else if OA is perpendicular to PA, PA is the tangent. Same is the case with point B.
Tangents from the same external point has same length.
MA = MB since they are the radii of the same circle with center M.
Hence, MA and MB meet all the requirements of the tangents.
Answer:
A.535 B.3 C.88.611 D.705.2
Step-by-step explanation:
You round all the way down
ok sweetheart so basicaly what u do is...
Sample Response: Each base must be treated separately. Since each base is raised to a negative exponent, they should both be in the denominator of the fractions. The simplified form of the expression has 1 in the numerator and r to the 8th power times s to the 5th power in the denominator
576577 is the right answer and the right to
Answer:
y=-4/9x+11/3
Step-by-step explanation:
Reminder: slope intercept form is y=mx+b where m= slope and b=y intercept
Two points are given; (6,1) and (-3,5)
First, find the slope
Reminder: slope is y2-y1/x2-x1
You can plug the numbers given into the equation to get 5-1/-3-6 which equals 4/-9
Now, we can use slope point form which is y-y1=m(x-x1)
Once again, plugging the numbers in (any one of the two points will work) will get
y-1=4/-9(x-6)
Simplifying it will get y=-4/9x+11/3.
