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alekssr [168]
2 years ago
6

No need for explanation only answer plsAlso is are the other ones correct?

Mathematics
1 answer:
koban [17]2 years ago
8 0

1. The area of the red carpet will be 1057t².

2. The diagram to justify the answer is diagram C.

3. The diagram to justify the answer is diagram C.

4. The model to justify the answer is diagram B.

<h3>How to calculate the area?</h3>

1. It should be noted that the area of the shape thats given in the question will be:

= Length × Width

Since the width is 1/6 of the diagram. This will be:

= 1/6 × 63

= 10.5

Therefore, the area of the red carpet will be:

Area = Length × Width

Area = 100.67 × 10.5

Area = 1057 feet²

Therefore, the area of the red carpet will be 1057t².

2. The diagram to justify the answer will be:

= 1/4 ÷ 8

= 1/4 × 1/8

= 1/32

The diagram is C.

3. The diagram to justify the answer will be:

= 4 ÷ 1/3

= 4 × 3

= 12

The diagram is C.

4. The model that justifies the answer will be:

= 5/12 × 2/5

= 10/60

= 1/6

The model to justify the answer is diagram B.

Learn more about area on:

brainly.com/question/25292087

#SPJ1

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natta225 [31]

3) We have

f(x) = \sec\left(\dfrac{\pi x}2\right) = \dfrac1{\cos\left(\frac{\pi x}2\right)}

which has vertical asymptotes (i.e. infinite discontinuities) whenever the denominator is zero. This happens for

\cos\left(\dfrac{\pi x}2\right) = 0

\implies \dfrac{\pi x}2 = \cos^{-1}(0) + 2n\pi \text{ or } \dfrac{\pi x}2 = -\cos^{-1}(0) + 2n\pi

(where n is any integer)

\implies \dfrac{\pi x}2 = \dfrac\pi2 + 2n\pi \text{ or } \dfrac{\pi x}2 = -\dfrac\pi2 + 2n\pi

\implies x = 1 + 4n \text{ or } x = -1 + 4n

So the graph of f(x) has vertical asymptotes whenever x=4n\pm1 and n\in\Bbb Z.

4) Given

h(t) = \begin{cases} t^3+1 & \text{if } t

we have the one-sided limits

\displaystyle \lim_{t\to1^-} h(t) = \lim_{t\to1} (t^3+1) = 1^3+1 = 2

and

\displaystyle \lim_{t\to1^+} h(t) = \lim_{h\to1} \frac{t+1}2 = \frac{1+1}2 = 1

The one-sided limits don't match, so the two-sided limit L does not exist. In other words, the limit does not exist at x=1 because the function approaches different values from the left and right side of x=1.

6 0
2 years ago
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