Step-by-step explanation:
f(g(10))
This is called a composite function. It's when you plug one function into another.
First, find g(10):
g(x) = √(x-9)
g(10) = √(10-9)
g(10) = √1
g(10) = 1
Then plug that into f(x):
f(x) = -9x - 9
f(g(10)) = -9 g(10) - 9
f(g(10)) = -9 (1) - 9
f(g(10)) = -9 - 9
f(g(10)) = -18
For No. 13 you need to calculate the distance each girl travels and compare to see whose distance is greater. The formula for distance is rate x time or d=rt. The rate is just how fast they consistently go.
Mia
d = r x t
d = 14 x 3/2
d = 21 miles
Chloe
d = r x t
d = 35 x 3/4 (btw 3/4 is just 45/60 simplified)
d = 105/4 = 26 1/4 miles
Final Answer: Chloe traveled further
For No. 14 we will recalculate Mia's distance but replace 1/5 hours with 2 hours because it says she will bike 30 minutes after Chloe had stopped. Afterwards we will compare Mia's new distance with Chloe's old distance.
Mia
d = r x t
d = 14 x 2
d = 28 miles
Final Answer: Yes Mia would be able to catch up to Chloe, and even surpass her in 30 minutes if Chloe stopped.
Answer:
see explanation
Step-by-step explanation:
note when x = - 3
(- 3)³ + 2(- 3)² + 4(- 3) + 21 = - 27 + 18 - 12 + 21 = 0
hence x = - 3 is a zero and (x + 3) is a factor and dividing gives
= (x + 3)(x² - x + 7)
For zeros equate to zero
(x + 3)(x² - x + 7) = 0
equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
x² - x + 7 = 0 ← solve using quadratic formula
x = (1 ± 
) / 2 = (1 ± 3i
) / 2
x = 
± 
zeros are x = - 3, x = ±
