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ad-work [718]
3 years ago
6

PLEASE HELP ME! I WILL GIVE YOU BRAINLEST!

Mathematics
1 answer:
vovikov84 [41]3 years ago
7 0
The correct answer is -8a+12b-36
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What is the equation of the line with a slope of 1/2 that passes through the point (-8, -2)?
Luba_88 [7]

Answer:

The answer is

y =  \frac{1}{2} x + 2 \\

Step-by-step explanation:

To find an equation of a line when given the slope and a point we use the formula

y -  y_1 = m(x -  x_1)

From the question we have

y + 2 =  \frac{1}{2} (x + 8) \\ y + 2 =  \frac{1}{2} x + 4 \\ y =  \frac{1}{2} x + 4 - 2

We have the final answer as

y =  \frac{1}{2} x + 2 \\

Hope this helps you

6 0
3 years ago
The product of the roots of x² 6x - 55 = 0 is:
Firdavs [7]
The roots of  x^{2} 6x-55=0 the answer is going to be

the roots is going to 3[1980/6}
x= 2.09284539
3 0
4 years ago
Read 2 more answers
Whats the slope help pls!
matrenka [14]
The right answer should be y=3x+2
3 0
3 years ago
7. Find the length of AB<br> please answer will mark brainelist :)
Julli [10]

Answer:

A) 17 m  B) 20.8 m

Step-by-step explanation:

I cannot mark on the image but you can find the length of A to the bottom of the shape by subtracting 26-11

26-11 = 15

I will label the triangle as ABC (AB the length we trying to find, BC is 15 *it is angle B to the intercept of A and the bottom of the shape, AC is 8 because it is parallel to the given length 8)

AB is the hypotenuse

We can use the pythagorean theorem  to find length AB (a^2 + b^2 = c^2)

a and b is the legs which is 8 and 15

8^2 + 15^2 = AB^2

64 + 225 = AB^2

289 = AB^2

√289 = AB (to undo a square, you use square roots)

√289 = 17

AB = 17 m

Now we need to find the hypotenuse of AC

the same thing, we did for problem A, use the pythagorean theorem

17^2 + 12^2 = AC^2

289 + 144 = AC^2

433 = AC^2

√433 = AC

√433 is <em>about </em>20.808...

round to the tenth as stated in the directions

AC = 20.8 m

7 0
2 years ago
Hello i would like help and the answer to this please; what is the nth term rule of
Paraphin [41]

Answer:

The nth term of the given sequence

a_{n} = a_{n-1} + (2n-1)

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given sequence  -5,-4,-1,4,11,20,31

a₀ = -5

a₁ = a₀ +1 = -5 +1   = -4

a₂ = a₁ + 3 = -4+3  = -1

a₃ = a₂ + 5 = -1 +5 = 4

a₄ = a₃ + 7 = 4 + 7  =11

a₅ = a₄ + 9 = 11+9 = 20

a₆ = a₅ + 11 =  20+11 = 31

a₇ = a₆ + 13 = 31 +13 =44

and so on

The nth term of the given sequence

a_{n} = a_{n-1} + (2n-1)

7 0
3 years ago
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