Do this for me pls im deprate
1 answer:
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Answer:
Therefore the length of QP = 3.4 units
Step-by-step explanation:
Given:
PQ = 2x + 1
XF = 7x - 4
PF = x
Q is the mid poimt of XF
∴ XQ = QF
QF = PQ - PF ..........( Q - F - P )
= 2x + 1 - x
∴ QF = x + 1
∴ XQ = QF = x + 1
TO Find:
QP = ?
Solution:
By Addition Property we have
Substituting the given values in above equation we get
(7x - 4) + x = (x +1) + (x +1) + x
8x -4 = 3x +2
8x - 3x + 4 + 2
5x = 6
∴
Now we require
QP = (2x + 1)
∴
Therefore the length of QP = 3.4 units
Answer:
x'-5x=0, or x''-25x=0, or x'''-125x=0
Step-by-step explanation:
The function is infinitely differentiable, so it satisfies a infinite number of differential equations. The required answer depends on your previous part, so I will describe a general procedure to obtain the equations.
Using rules of differentiation, we obtain that . Differentiate again to obtain,
. Repeating this process,
.
This can repeated infinitely, so it is possible to obtain a differential equation of order n. The key is to differentiate the required number of times and write the equation in terms of x.