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Reika [66]
3 years ago
7

What is the circumference of circle with a diameter of 9 feet? Use 3.14 for tt

Mathematics
2 answers:
Gennadij [26K]3 years ago
7 0
C= pi * d
C= 3.14 * 9
C= 28.26 ft
ankoles [38]3 years ago
4 0

Answer:

28.26

Step-by-step explanation:

The formula for calculating diameter is π<em>d</em> (pi times the diameter), so 3.14 times 9 is 28.26.

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HELPPP PLEASE!!! I REALLY NEED HELP PLEASE EXPLAIN UR ANSWER ITS DUE SOONNN
Gemiola [76]

Answer:

C

Step-by-step explanation:

6 0
3 years ago
In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.
jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}

\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}

\text{The weight of average pumpkin}=5\text{ kg}

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

3 0
4 years ago
Read 2 more answers
Given the equation below, solve for the variable t.<br><br> p+o−wt=4b
kotegsom [21]
P+o-wt=4b
-wt=4b-p-o
t=(4b-p-o)/-w

mark as brainliest if it’s helpful
8 0
3 years ago
Find 48% of 30. Please help
baherus [9]

Answer:

14.4 would be the answer hope this is helpful

Step-by-step explanation:

14.4/30= 48%

4 0
3 years ago
Read 2 more answers
Noah has a total of 47 video games. He only buys action and sports games. He has 21 more action games than sport games. How many
Zanzabum
A-action games
s-sports games

a+s=47
a=s+21

I replace the action games in the first equation

s+21+s=47
2s+21=47
2s=47 - 21
2s=26
s=26:2
s=13 number of sport games
a=13+21
a=34 number of action games
8 0
3 years ago
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