For 1 the equation of the parabola is y = x^2 - 8x + 3
For 2 the equation of the parabola is y = -2x^2 - 3x + 1
For 3 the equation of the parabola is y = -x^2 + 5x - 4
Alright, so plugging it in, we get 2(-4)^2=2(2)^4+3^2-(-4)^2+2^4. Use PEMDAS with parenthesis and exponents to then get (2)(16)+9-16+16. Multiplying 1 and 16, we get 32+41-16+16=73
Answer:- A reflection of the line segment across the line y = –x .
Explanation:-
A reflection over the line y = -x, the x-coordinate and y-coordinate interchange their places and they are negated (the signs are changed).
Given :- A line segment has endpoints at (–1, 4) and (4, 1) such that it reflects produce an image with endpoints at (–4, 1) and (–1, –4).
(-1, 4)→(-4, 1) and
(4, 1)→(-1, -4)
Thus this shows a reflection of the line segment across the line y = –x.
Answer:
(h+g)=n➗2 is the answer. happy to help you
