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3 years ago

Please provide a solution

Mathematics

1 answer:

Andrei [34K]3 years ago

7 0

<h2>Answer: Based on hint and given formula, we can complete the problem. The question asks for square feet of grass so we know that we are solving for the area, A. It also tells us the height (looking downward) of the field is 75 ft,h, while the two bases are 125 ft and 81 ft (b1 and b2). So we can solve the equation. A = 75((125+81)/2) A = 75(206/2) A = 75(103) A = 7725 The area of the field is 7725 square feet.</h2><h2 /><h2>Step-by-step explanation: Hope it helps </h2>

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HELP ASAP TEST IS OMOST OVER!!!!!!!!!!

svet-max [94.6K]

Answer: C)46 ft

Step-by-step explanation:

We know that the circumference of a circle can be calculated with this formula:

$C=2\pi r$

Where "r" is the radius of the circle.

Since John is putting a fence around his garden that is shaped like a half circle and a rectangle, then we can find how much fencing he needs by making this addition:

$Fencing=\frac{2\pi r}{2}+2l+w$

Where "l" is the lenght of the rectangle and "w" is the width of the rectangle.

Since we know that the radius of the circle is half its diameter, we can find "r". This is:

$r=\frac{7ft}{2}=3.5ft$

Then, substituting values (and using $\pi=\frac{22}{7}$ ), we get:

$Fencing=\frac{2(\frac{22}{7})(3.5ft)}{2}+2(14ft)+7ft=46ft$

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3 years ago

Expres each of the folowing as a single matrix.

Elden [556K]

Answer:

$\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]$

Step-by-step explanation:

If you have two matrices:

$A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}a+e&b+f\\c+g&d+h\end{array}\right]$

We have:

$A=\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]\\and\\B=\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]$

And we need to express as a single matrix:

$A+B=\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}6+(-2)&-3+8\\10+3&-1+(-12)\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}6-2&5\\13&-1-12\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]$

The answer is:

$\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]$

It is expressed as a single matrix.

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Y = -4x
**************************************************************************

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