A student graphs f(x)= 3x - 2 On the same grid, the student graphs the function g which is a transformation off made by subtract
ing 4 from the input off. Describe and correct the error the student made when graphing 9 fr) = 3x-2 5 X Х Which of the following is the function that the student graphed? Choose the correct answer below
O A. The transformation of f obtained by subtracting 4 from the output off
B. The transformation of f obtained by multiplying the input of g by f
O C. The transformation off obtained by adding 4 to the output off
OD. The transformation of f obtained by multiplying the output of g by f.
O E The transformation of f obtained by adding 4 to the input of f 
O A. The transformation of f obtained by subtracting 4 from the output off
B. The transformation of f obtained by multiplying the input of g by f
O C. The transformation off obtained by adding 4 to the output off
OD. The transformation of f obtained by multiplying the output of g by f.
O E The transformation of f obtained by adding 4 to the input of f
1 answer:
You might be interested in
Answer:
A 95% confidence interval for the true mean is [$3.39, $6.01].
Step-by-step explanation:
We are given that a random sample of 10 parking meters in a resort community showed the following incomes for a day;
Incomes (X): $3.60, $4.50, $2.80, $6.30, $2.60, $5.20, $6.75, $4.25, $8.00, $3.00.
Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;
P.Q. = ~
where, = sample mean income =
= $4.70
s = sample standard deviation = = $1.83
n = sample of parking meters = 10
= population mean
<em>Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>
<u>So, 95% confidence interval for the population mean, </u><u> is ;</u>
P(-2.262 < < 2.262) = 0.95 {As the critical value of t at 9 degrees of
freedom are -2.262 & 2.262 with P = 2.5%}
P(-2.262 < < 2.262) = 0.95
P( <
<
) = 0.95
P( <
<
) = 0.95
<u>95% confidence interval for</u> = [
,
]
= [ ,
]
= [$3.39, $6.01]
Therefore, a 95% confidence interval for the true mean is [$3.39, $6.01].
The interpretation of the above result is that we are 95% confident that the true mean will lie between incomes of $3.39 and $6.01.
Also, the margin of error =
= = <u>1.31</u>