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zavuch27 [327]
3 years ago
10

If graphs have a linear equations in a system are concurrent having the same slope and the same y-intercept what does that mean

about possible solutions
Mathematics
1 answer:
Schach [20]3 years ago
8 0

Answer:

Infinite Amount of Solutions

Step-by-step explanation:

Since we have concurrent systems (same slope + same y-int), we know that the systems of equations would be the <em>exact</em> same line. If that is the case, the we would know that ANY value input would work. You could even test it mathematically, and it would give you infinite amount of solutions.

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3 0
3 years ago
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Can someone pls help??
Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

3 0
3 years ago
What is the general term equation, an, for the arithmetic sequence 9, 5, 1, −3, . . . , and what is the 21st term of this sequen
marin [14]
Hello : 
<span>the general term equation, an, for the arithmetic sequence is : 
An = A1+d(n-1)
A1 : the first term   and : d the common diference
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An = 9-4(n-1)
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4 0
3 years ago
A game uses tokens. Two-sixths of the tokens are blue. Three-sixths of the tokens are gold. What fraction of the tokens are eith
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Answer:

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Step-by-step explanation:

First we need to add the blue tokens (two-sixths) plus the gold tokens (two-sixths) when you add those you get five-sixths and since we are dealing with sixths we would subtract five-sixths from six-sixths

4 0
3 years ago
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