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Nadusha1986 [10]
2 years ago
9

1 x - 37 =- 84 Solve please

Mathematics
1 answer:
MAXImum [283]2 years ago
5 0

Answer:

Hello there!

You question is

1x - 37 = -84

am i right?

Your answer is :

<h2>x = - 47</h2>

Step-by-step explanation:

So, since 1x and x are basically the same, you don't really have to do anything with that.

You add 37 on both sides.

Therefore, your answer is x = -47.

Hope this helps!

(Note: if there are more instructions to this question, please let me know.) :)

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yanalaym [24]

-1/3(px-2) = 9

ok! so first we want to isolate x.

multiply both sides by -3/1 (this is the reciprocal of -1/3)

(px-2) = -27

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hope this helped!

8 0
3 years ago
Can someone please help me with this question?!? I am so confused and I don't know how to answer it.
lbvjy [14]

9514 1404 393

Answer:

  a. f(0) = 1

  b. DNE (does not exist)

  c. DNE

  d. lim = 3

Step-by-step explanation:

The function exists at a point if it is defined there. The function is defined anywhere on the solid line and at solid dots. It is not defined at open circles. So, the function is defined everywhere except (2, 3), which has an open circle.

The open circle at (0, 4) prevents the function from being doubly-defined at x=0, since it is already defined to be 1 at x=0.

This discussion tells you ...

  f(0) = 1

 f(2) does not exist. There is a "hole" in the function definition there.

__

The function has a limit at a point if approaching from the left and approaching from the right have you approaching that same point.

Consider the point (1, 2). The graph is a solid line through that point. Approaching from values less than x=1, we get to the same point (1, 2) as when we approach from values greater than x=1.

Similarly, consider the point (2, 3). Approaching from values of x less than 2, we get to the same point (2, 3) as when we approach from x-values greater than 2. The limit at x=2 is 3. The only difference from the previous case is that the function is not actually defined to be that value there.

__

Now consider what happens at x=0. When we approach from the left, we approach the point (0, 4). When we approach from the right, we approach the point (0, 1). These are different points. Because they are different coming from the left and from the right, we say "the limit as x→0 does not exist."

__

In summary, ...

  a) f(0) = 1

  b) lim x → 0 does not exist

  c) f(2) does not exist

  d) lim x → 2 = 3

_____

<em>Additional comment</em>

The significance of the function not being defined at a point where the limit exists, (2, 3), is that <em>the function is not continuous there</em>. This kind of discontinuity is called "removable", because we could make the function continuous at x=2 by defining f(2) = 3 (that is, "filling the hole").

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2 years ago
The sum of two numbers is twenty-four. The difference of the two numbers is four.
RSB [31]

Answer:

x + y = 24

x - y = 4

Now, add these two equations.

You get,

2x = 28

x =  \frac{28}{2}

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Given,

x + y = 24

14 + y = 24

y = 24 - 14

y = 10

You can test this to the other equation as well.

x - y = 4

14 - 10 = 4

Hence, the two numbers are 14 and 10.

3 0
2 years ago
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