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4 years ago

12/19*.............................= -12/19

Mathematics

1 answer:

melamori03 [73]4 years ago

3 0

Answer:

$\frac{12}{19} \times \underline{\bold{-1}} = -\frac{12}{19}$

Step-by-step explanation:

$\frac{12}{19} \times ..... = -\frac{12}{19}$

= $\frac{\frac{12}{19}}{-\frac{12}{19}}$

= $\frac{12}{19} \times -\frac{19}{12}$

= $-\frac{228}{228}$

= $\bold{-1}$

So, the appropriate value to complete it is -1

#CMIIW ^^

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What is the solution to the equation below? riund your answer to two decimal places. (24) log(3x) = 60

Amanda [17]

The answer is: " x = 105.41 " .

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Explanation:

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Given: " 24 log (3x) = 60 " ; Solve for "x" .

The default is to assume "base 10" for the "logarithm".

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Start by dividing each side of the equation by "24" ;

→ [ 24 log(3x) ] / 24 = 60 / 24 ;

to get:

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log (3x) = 2.5 ;

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Rewrite as: log₁₀ (3x) = 2.5 ;

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Using the property of logarithms:

⇔ 10⁽²·⁵⁾ = 3x ;

↔ 3x = 10⁽²·⁵⁾ ;

→ 10^ (2.5) = 316.2277660168379332 ;

→ 3x = 316.227766016837933 ;

Divide each side of the equation by "3" ;

to isolate "x" on one side of the equation;

and to solve for "x" ;

→ 3x / 3 = 316.2277660168379332 / 3 ;

to get:

→ x = 105.4092553389459777333 ;

→ round to 2 (two) decimal places;

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→ " x = 105.41 " .

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Hope this helps!

Best wishes to you!

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3 years ago

A rectangular sign has length of 3 and 1/2 ft and a width of 1 and 1/8 ft. Will the area of the sign be greater or less than 3 a

zavuch27 [327]

Answer:

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Area is greater than $3\frac{1}{2}$ sq ft.

Step-by-step explanation:

Length of rectangular sign board = $3\frac{1}{2}$ ft

Width of rectangular sign board = $1\frac{1}{8}$ ft

Area of a rectangle is given by the formula:

$A = Length \times Width$

To find the area, we are going to multiply $3\frac{1}{2}$ with $1\frac{1}{8}$ .

$1\frac{1}{8}$ is greater than 1.

Therefore the multiplication will be greater than $3\frac{1}{2}$ .

Hence, we can say that area will be greater than $3\frac{1}{2}$ sq ft.

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$A = 3\dfrac{1}{2}\times 1\dfrac{1}8\\\Rightarrow A = \dfrac{7}{2}\times \frac{9}8\\\Rightarrow A = \dfrac{63}{16}\\\Rightarrow A = 3\dfrac{15}{16}\ sq\ ft$

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3 years ago

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If $\mathbf{\Delta > 0}$ , it has 2 real solutions.

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More can be learned about the discriminant of quadratic functions at brainly.com/question/19776811

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