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Nataly [62]
2 years ago
5

Simplify the following expression: -7(3e-2f+4)+6e-2

Mathematics
1 answer:
tankabanditka [31]2 years ago
3 0

Answer:

-15e+14f-30

Step-by-step explanation:

First using distributive property to expand the first term:

-21e+14f-28+6e-2

Combining like terms:

-15e+14f-30

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Factor strings for 36
Marina CMI [18]
Factor strings for 36:

6 x 6
2 x 18
3 x 12
4 x 9
2 x 2 x 3 x 3
2 x 2 x 9
4 x 3 x 3
6 x 2 x 3

Hope that helped :D
4 0
3 years ago
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Faith started last week with $1,100 in her checking account. During the week, she wrote the checks below.
quester [9]

Answer:

the correct answer is A

Step-by-step explanation:


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3 years ago
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A box contains blue, red, and green pens. 25% of the pens are green and 35% are red. 48 blue pens cannot be used, but the remain
Mama L [17]

Answer: number of blue pen = 128

Number of pen in the box = 320

Step-by-step explanation:

6 0
3 years ago
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For a quadratic function ƒ(x)=ax2+bx+c, ƒ(−1)<1, ƒ(1)>−1, and ƒ(3)<−4. What could be the sign of a?
denis23 [38]

Answer:

"a" must be negative

Step-by-step explanation:

The slope between points (-1, 1) and (1, -1) is a minimum of (-1-1)/(1-(-1)) = -1.

The slope between points (1, -1 and (3, -4) is a maximum of (-4-(-1))/(3-1) = -3/2.

Thus, as x increases, the slope is decreasing. In order for that to be the case, the value of <em>a</em> must satisfy a < 0.

4 0
3 years ago
ZE is the angle bisector of measure YEX and the perpendicular bisector of GF, GX is the angle bisector of measure YGZ and the pe
den301095 [7]

Answer:

C

Step-by-step explanation:

The center of inscribed circle into triangle is point of intersection of all interior angles of triangle.

The center of circumscribed circle over triabgle is point of intersection of perpendicular bisectors to the sides.

Circumscribed circle always passes through the vertices of the triangle.

Inscribed circle is always tangent to the triangle's sides.

In your case angles' bisectors and perpendicular bisectors intesect at one point, so point A is the center of inscribed circle and the center of corcumsribed circle. Thus, these circles pass through the points X, Y, Z and G, E, F, respectively.

7 0
3 years ago
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