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professor190 [17]
3 years ago
8

Tarnish on silver is the compound Ag2OAg2O. A tarnished silver spoon is placed in an aluminum pan of boiling water. When enough

salt is added so that the solution conducts electricity, the tarnish disappears. Imagine that the two halves of this redox reaction were separated and connected with a wire and a salt bridge.
Chemistry
1 answer:
Leya [2.2K]3 years ago
8 0

Answer:

The answer is "2.459".

Explanation:

The cell potential or emf norm  = oxidation pot. of anode -oxidation pot. of cathode

When the pot oxidizer is the opposite of a red pot size it's been transformed to either the redox reaction so that anode was its higher oxide pot material that means (AL) so,

\to emf=1.66-(-0.799) \\\\ \to emf=1.66+0.799) \\\\ \to emf =2.459

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Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas. pcl3(g) + cl2(g) equilibrium reaction ar
vladimir1956 [14]

The question is incomplete, here is the complete question:

Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas:

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

A gas vessel is charged with a mixture of PCl_3(g) and Cl_2(g), which is allowed to equilibriate at 450 K. At equilibrium the partial pressures of the three gases are p_{PCl_3(g)} = 0.126 atm , p_{Cl_2(g)} = 0.156 atm , and p_{PCl_5(g)} = 1.60 atm. What is the value of K_p at this temperature?

<u>Answer:</u> The K_p for the given reaction is 81.4

<u>Explanation:</u>

For the given chemical equation:

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The expression of K_p for above reaction follows:

K_p=\frac{p_{PCl_5}}{p_{Cl_2}\times p_{PCl_3}}

We are given:

p_{PCl_5}=1.60atm\\p_{PCl_3}=0.126atm\\p_{Cl_2}=0.156atm

Putting values in above equation, we get:

K_p=\frac{1.60}{0.156\times 0.126}\\\\K_p=81.4

Hence, the K_p for the given reaction is 81.4

8 0
3 years ago
What is the strongest type of intermolecular force between solute and solvent in each solution?
Dvinal [7]

London Dispersion Force between solute and solvent in each solution is the strongest type of intermolecular force.

<h3>What is London Depression Force ?</h3>

There are 4 types of intermolecular forces -

  • Dispersion Force
  • Dipole–Dipole
  • Hydrogen Bonding, and
  • Ion-Dipole.

The London dispersion force is a transient attractive attraction that occurs when two nearby atoms' electrons occupy locations that cause the atoms to form temporary dipoles. This force is also known as induced dipole-induced dipole attraction.

Example ; If these atoms or molecules come into contact with each other, dispersion forces exist between them. Consider the London dispersion forces between two chlorine molecules. Both chlorine atoms are connected in this case via a covalent connection formed by the equal sharing of valence electrons between two chlorine atoms.

Thus from the above solution we can say that in between these solutions London Depression force is the strongest force.

To know more about Depression Force please click here ; brainly.com/question/1455074

#SPJ4

8 0
2 years ago
If you go to the moon, what will happen to your weight and mass?
spin [16.1K]

Answer:

Your weight will change... because weight is the effect gravity has on matter... but mass will stay the same

Explanation:

4 0
3 years ago
What’s the difference in the number of protons of an atom of lithium and an atom of chlorine :)) I need this answer quick
Katarina [22]

Answer:

14

Explanation:

The lithium atom has 3, which is its atomic number. (Atomic number is the number of protons in the nucleus of an atom, which determines the chemical properties of an element and its place in the periodic table.) The chlorine atom has 17, so if you find the difference, it would be 14.

5 0
3 years ago
In a titration of 50 ML of 0.20m NaOH is used to neutralize 10.0 ML of HCL. Calculate the molarity of the acid
Svet_ta [14]

Answer:

1M

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

NaOH + HCl —> NaCl + H2O

From the equation above,

nA (mole of acid) = 1

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of base) = 50mL

Mb (Molarity of base) = 0.2M

Va (volume of acid) = 10mL

Ma (Molarity of acid) =?

Using MaVa/MbVb = nA/nB, we can calculate the molarity of the acid as follow:

Ma x 10/0.2 x 50 = 1

Cross multiply to express in linear form

Ma x 10 = 0.2 x 50

Divide both side by 10

Ma = (0.2 x 50)/10

Ma = 1M

The molarity of the acid is 1M

3 0
3 years ago
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