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N76 [4]
3 years ago
13

How many molecules of aspartame are present in 1.00 mg of aspartame?

Chemistry
1 answer:
kobusy [5.1K]3 years ago
5 0

Answer:

0.2 x 10^19

Explanation:

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⇒with V1 = the volume of the original NaOH solution = TO BE DETERMINED

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⇒with V2 = the volume  of the NaOH solution we want to prepare = 500 mL = 0.500 L

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V2 = (3.0 M * 0.500L) / 19.0 M

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