A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
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Answer: 9675
Step-by-step explanation: u don’t want to know do u
Answer:
The mistake is that 4x+x = 5x not 4x
Step-by-step explanation:
4x + x = 30 –6
Combine like terms
5x = 24
Divide each side by 5
5x/5 = 24/5
x = 24/5
The mistake is that 4x+x = 5x not 4x
Answer:
I wanna say the first picture second answer choice. Please tell me if I am right.
Step-by-step explanation:
<span>y-10 = -5/4x + 30/4 represents a linear function; we know that because both x and y have the power 1.
We could put this equation into one of several forms.
Suppose we wanted to put it into slope-intercept form. Then </span><span>y-10 = -5/4x + 30/4 becomes y = 10 + 30/4 - (5/4)x, or y = 35/2 - (5/4)x. Thus, this line has the slope -5/4 and the y-intercept (0, 35/2).
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