Answer: 15! or 1307674368000
Step-by-step explanation:
According to the permutations , if we arrange n things in order , then the total number of ways to arrange them = n!
Similarly , when health inspector inspects 15 restaurants in town once each week, the number of different orders can be made for these inspections = 15!
= 15 x 14 x 13 x 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1
=1307674368000
Hence, the number of different orders can be made for these inspections = 15! =1307674368000
We have:
(30x²+23x+16)/(cx+3) - 13/(cx+3) = 6x+1
(30x²+23x+16 - 13)/(cx+3) = 6x+1
(30x²+23x+3)/(cx+3) = 6x+1
30x²+23x+3 = (cx+3)(6x+1)
30x²+23x+3 = 6cx²+cx+18x+3
30x² + 23x + 3 - 6cx² - cx - 18x - 3 = 0
(30 - 6c)x² +(5 - c)x = 0
6(5 - c)x² +(5 - c)x = 0
(5 - c)(6x² +x) = 0, and x∈ R\ {3/c} ⇒ 5 - c = 0 ⇒ c = 5.
A) Probability that at least one of these golfers makes a hole in one on the 10th hole at the same tournament is
<span>=1−(<span>2493/2494</span><span>)^<span>5
=1-(0.99)^5
= 1- 0.96
=0.4
b) T</span></span></span><span>he probability that all of these golfers make a hole-in-one on the 10th hole at the same tournament
=</span>(<span>1/2494</span><span>)<span>5
</span></span>
which is nearly zero.
Answer:
The second option
Step-by-step explanation:
c=
c=20 m
It’s four because you subtract 2 minus negative 2
