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AlekseyPX
3 years ago
7

-5(m+4)-10(8-5m) which’s is this

Mathematics
2 answers:
Darina [25.2K]3 years ago
3 0
-5m-20-80+50m=0
45m=100
m= 20/9
Mkey [24]3 years ago
3 0

Answer:

\large\boxed{45m-100}

Step-by-step explanation:

-5(m+4)-10(8-5m)\\\\\text{use the distributive property}\\\\=(-5)(m)+(-5)(4)+(-10)(8)+(-10)(-5m)\\\\=-5m-20-80+50m\\\\\text{combine like terms}\\\\=(-5m+50m)+(-20-80)\\\\=45m-100

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What is the solution to this equation x -9=5​
lukranit [14]

Answer:

x = 14

Step-by-step explanation:

x- 9 = 5

Note the equal sign, what you do to one side, you do to the other. Isolate the variable, x. Add 9 to both sides of the equation:

x - 9 (+9) = 5 (+9)

x = 5 + 9

x = 14

x = 14 is your answer.

~

7 0
3 years ago
An Archer shoots an arrow horizontally at 250 feet per second. The bullseye on the target and the arrow are initially at the sam
Genrish500 [490]

Answer:

<h2>1.84feet</h2>

Step-by-step explanation:

Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;

Range R = U\sqrt{\frac{H}{g} }

U is the velocity of the arrow

H is the maximum height reached = distance below the bullseye reached by the arrow.

R is the horizontal distance covered i.e the distance of the target from the archer.

g is the acceleration due to gravity.

Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?

On substitution,

60 = 250\sqrt{\frac{H}{32}} \\\frac{60}{250} = \sqrt{\frac{H}{32}}\\\frac{6}{25} = \sqrt{\frac{H}{32}

Squaring both sides we have;

(\frac{6}{25} )^{2} = (\sqrt{\frac{H}{32} } )^{2} \\\frac{36}{625} =  \frac{H}{32} \\625H = 36*32\\H = \frac{36*32}{625} \\H = 1.84feet

The arrow will hit the target 1.84feet below the bullseye.

5 0
3 years ago
How old is jared, the one who can't read?
Semmy [17]
Who is jared and ur options are??
3 0
3 years ago
Read 2 more answers
Can anyone pls help me with this I'll mark as brainlist for correct answer please do explain in detail each answers Ty! (I'm pre
densk [106]

<u>Question 8</u>

a^2 + 7a + 12

= (a+3)(a+4)

When factorising a quadratic, the product of the two factors should equal the constant term (12), and the sum of the two factors should equal the linear term (7). To find the two factors, list out the factors of 12 (1x12, 2x6, 3x4) and identify the pair that adds up to 7 (3+4).

An alternative method if you get stuck during your exam would be to solve it algebraically using the quadratic formula and then write it in the factorised form.

a = (-7 +or- sqrt(7^2 - 4(1)(12)) / 2(1)

= (-7 +or- sqrt(1))/2

= -3 or -4

These factors are the negative of the values that would go in the brackets when written in factorised form, as when a = -3 the factor (a+3) would equal 0. (If it were positive 3 instead, then in the factorised form it would be a-3).

<u>Question 10</u>

-3(x - y)/9 + (4x - 7y)/2 - (x + y)/18

Rewrite each fraction with a common denominator so you can combine the fractions into one.

= -6(x - y)/18 + 9(4x - 7y)/18 - (x + y)/18

= (-6(x - y) + 9(4x - 7y) - (x + y)) /18

Expand the brackets and collect like terms.

= (-6x + 6y + 36x - 63y - x - y)/18

= (29x - 58y)/18

= 29/18 x - 29/9 y

7 0
2 years ago
7.05, 5.07,7.5,0.57 least to greatest
Rudiy27

0.57 , 5.07 , 7.05 , 7.5

7 0
3 years ago
Read 2 more answers
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