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3 years ago

The distance of a point P(x, y) from the origin O(0, 0) is given by OP=__

Mathematics

1 answer:

Naily [24]3 years ago

4 0

Answer:-

$\boxed{\sf \sqrt{x^2+y^2}}$

Explanation:-

P(x,y)
O(0,0)

We know distance formula

$\boxed{\sf \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}$

$\\ \sf\longmapsto OP=\sqrt{(0-x)^2+(0-y)^2}$

$\\ \sf\longmapsto OP=\sqrt{(-x)^2+(-y)^2}$

$\\ \sf\longmapsto OP=\sqrt{x^2+y^2}$

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3 years ago

Which number sentence is true? A. –2.0 + (–0.5) = 2.5 B. –4.5 + 6.5 = –2.0 C. 3.0 + (–0.5) = –2.5 D. 5.5 + (–2.5) = 3.0

Soloha48 [4]

<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

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↬ ʜᴀɴɴᴀʜ ♡

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3 years ago

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There is a construction zone on a highway. The speeds of vehicles passing through this construction zone are normally distribute

bonufazy [111]

The percentage of vehicles passing through this construction zone that are traveling at a speed of 50 and 57 miles per hour

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3 years ago

A rectangular parking lot must have a perimeter of 440 feet and an area of at least 8000 square feet. Describe the possible leng

tangare [24]

Answer:

The possible parking lengths are 45.96 feet and 174.031 feet

Step-by-step explanation:

Let x be the length of rectangular plot and y be the breadth of rectangular plot

A rectangular parking lot must have a perimeter of 440 feet

Perimeter of rectangular plot =2(l+b)=2(x+y)=440

2(x+y)=440

x+y=220

y=220-x

We are also given that an area of at least 8000 square feet.

So, $xy \leq 8000$

So, $x(220-x) \leq 8000$

$220x-x^2 \leq 8000$

So, $220x-x^2 = 8000\\-x^2+220x-8000=0$

General quadratic equation : $ax^2+bx+c=0$

Formula : $x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-220 \pm \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=\frac{-220 + \sqrt{220^2-4(-1)(-8000)}}{2(-1)} , \frac{-220 - \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=45.96,174.031$

So, The possible parking lengths are 45.96 feet and 174.031 feet

3 0

3 years ago

If you roll two fair dice repeatedly, what is the probability that you will get a sum of 4 before you get a sum of 5 ? (a) (b) (

AlexFokin [52]

Answer:

The probability that you will get a sum of 4 before you get a sum of 5 is $\frac{1}{12}$

Step-by-step explanation:

Given : If you roll two fair dice repeatedly.

To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?

Solution :

When two dice are rolled the outcomes are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total number of outcomes = 36

Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3

The probability that you will get a sum of 4 before you get a sum of 5 is

$P=\frac{3}{36}$

$P=\frac{1}{12}$

Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is $\frac{1}{12}$

5 0

3 years ago

The distance of a point P(x, y) from the origin O(0, 0) is given by OP=__​

The distance of a point P(x, y) from the origin O(0, 0) is given by OP=__