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grandymaker [24]
3 years ago
8

Without solving, identify whether each of the following equations has a unique solution, no solution, or infinitely many solutio

ns.
3.2 + 6 = -8
0 1 solution
O No Solution
O Infinite solutions
Mathematics
1 answer:
Luden [163]3 years ago
7 0

Answer:

No solution

Step-by-step explanation:

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A Government company claims that an average light bulb lasts 270 days. A researcher randomly selects 18 bulbs for testing. The s
Fofino [41]

Answer:

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question, we have that:

\mu = 270, \sigma = 90, n = 18, s = \frac{90}{\sqrt{18}} = 21.2

What is the probability that 18 randomly selected bulbs would have an average life of no more than 260 days?

This is the pvalue of Z when X = 260. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{260 - 270}{21.2}

Z = -0.47

Z = -0.47 has a pvalue of 0.3192.

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

5 0
3 years ago
Convert to an improper fraction. Type in your answer with the negative in the numerator. -11 1/3
vovangra [49]
The answer to the question is :

-11*3+1/3
=-33+1/3
= -32/3

Therefore, answer = -32/3
                                 


6 0
3 years ago
Read 2 more answers
Which transformations are needed to change the parent cosine function to y= 3cos(10(x-pi) )?
denpristay [2]
<span>The parent cosine function can be transformed and translated. So, from the basic function cos(x) we can obtain function acos(bx+c). In our case, a=3- amplitude, b=10- the period change and c=-pi- the phase shift. So, the parent cosine function is mutiplied with 3 (which gives the amplitude of the function, 3*0.5=1.5). The period of the function is changed, and is 2pi/b=2pi/10=pi/5 and the cos(x) is phase shifted for c/b=-pi/10.</span>
6 0
3 years ago
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Which equation describes a rational function with x-intercepts at –4 and 2, a vertical asymptote at x = 1 and x = –1, and a hori
Naily [24]

Answer:

d on edge

Step-by-step explanation:

-3(x+4)(x-2)/x^2-1`

5 0
3 years ago
Im sooo confused please help!
Harrizon [31]
So what it is asking you to do is compare the amount of oats to the other ingredients. ex, 2 cups of oats for every 0.5 cup of quinoa. just do that for the rest of them
8 0
3 years ago
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