(08.05 LC) Which two-dimensional shape can be rotated about the y-axis to create a cone?

Mathematics

2 answers:

gogolik [260]3 years ago

6 0

Answer:

Right triangle

Step-by-step explanation:

Just imagine a rotating door in the shape of a right triangle.

Illusion [34]3 years ago

4 0

Any right triangle can.

You might be interested in

Ana drew a map of the Panama Canal. In the scale Ana used for the map 4 centimeters represents 20 kilometers. The actual length

Serga [27]

the length in centimeters of the Panama Canal on Anas map is $16.4cm$ .

<u>Step-by-step explanation:</u>

Here we have , Ana drew a map of the Panama Canal. In the scale Ana used for the map 4 centimeters represents 20 kilometers. The actual length of the Panama Canal is 82 kilometers. We need to find What is the length in centimeters of the Panama Canal on Anas map . Let's find out:

In the scale Ana used for the map 4 centimeters represents 20 kilometers , that means for 4 cm we have 20 km , So for 1 km we have :

⇒ $\frac{4}{20}cm$

⇒ $\frac{4(5)}{20(5)}cm$

⇒ $\frac{20}{100}cm$

⇒ $0.2cm$

Hence , for 82 km we have :

⇒ $0.2cm(82)$

⇒ $(82(0.2))cm$

⇒ $16.4cm$

Therefore , the length in centimeters of the Panama Canal on Anas map is $16.4cm$ .

5 0

3 years ago

HOW CAN ARITHMETIC AND GEOMETRIC SEQUENCES BECOME LINEAR AND EXPONENTIAL FUNCTIONS?

aliina [53]

The formula of an arithmetic sequence is the following :
$u_n=r\times n+u_0\text{ wherein r is the rate of the sequence}
\\\text{and u0 the first value}\\\text{The above formula is linear wherever }u_0=0.$
A geometric sequence is in the form:
$u_n=u_0r^n\text{, again u0 the first value and r the rate. }\\\text{If }u_0=1\text{ the formula becomes:}\\u_n=r^n=e^{n\log r}\text{ which is an exponential formula.}$

3 0

3 years ago

What is the vortex of the graph of the quadratic function<br><img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%20%20%7B%7D%5E

Murrr4er [49]

$\bf \textit{vertex of a vertical parabola, using coefficients}
\\\\
\stackrel{f(x)}{y}=\stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{-2}
\qquad \qquad
\left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)
\\\\\\
\left( -\cfrac{2}{2(1)}~~,~~-2-\cfrac{2^2}{4(1)} \right)\implies \left( -1~~,~~-2-1 \right)\implies (-1~,-3)$