B. Is the right answer
First you have to take the common elements then use an identity/formula to get the rest
x^3 - 3x^2 + x-3
x^2 (x-3) +1 (x-3)
(x^2 +1) (x-3)
(x-1)(x+1)(x-3) {using a^2-b^2 on x^2-1^2}
Answer:
y= -3/4x - 3
Step-by-step explanation:
-3/4 is the slope, so you replace m with the slope.
The y intercept is -3. If x is 4, and y is -6, we can plug that into an equation to find the y intercept. y=mx+b can change to -6= -3/4 * 4 + b. B = -3.

now, we get critical points from zeroing out the derivative, and also from zeroing out the denominator, but those at the denominator are critical points where the function is not differentiable, namely a sharp spike or cusp or an asymptote.
so, from zeroing out the derivative we get no critical points there, from the denominator we get x = 8, but can't use it because f(x) is undefined.
therefore, we settle for the endpoints, 4 and 6,
f(4) =3 and f(6) = 7
doing a first-derivative test, we see the slope just goes up at both points and in between, but the highest is f(6), so the absolute maximum is there, while we can take say f(4) as the only minimum and therefore the absolute minumum as well.
Let
c-------> the number of chores
we know that
--------> inequality
Solve for c

therefore
<u>the answer is</u>
The minimum number of chores that Janie must do is 
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And

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To find the y-intercept of any equation just need to put 0 (( zero )) instead of the x in the equation...
<h2>
Let's do it....</h2>
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In f ( x ) :




Thus :

##############################
In g ( x ) :





Thus :

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The positive difference in the y-intercept value of f ( x ) and g ( x ) is :

So write this in the box : 1
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And we're done....
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