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3 years ago

7

Which two-dimensional net does not represent a three-dimensional rectangular prism?

2 answers:

spin [16.1K]3 years ago

7 0

the second one

Step-by-step explanation:

because if you see good the second one have the dimensional in the same way

julia-pushkina [17]3 years ago

7 0

Answer:

the second one

Step-by-step explanation:

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A ball has a volume of 4 cubic inches (in3). Use the fact that 1 inch is equal to 2.54 cm to convert this volume to cubic centim

Marina86 [1]

Answer:

V = 65.548 cm³

Step-by-step explanation:

We have,

Volume of a ball is 4 cubic inches or $4\ \text{inch}^3$ .

We know that, 1 inch = 2.54 cm

It is required to convert this volume to cubic centimetre or $\text{cm}^3$ .

$4\ \text{inch}^3=4\ \text{inch}^3\times (\dfrac{2.54\ \text{cm}}{1\ \text{inch}})^3\\\\V=65.548\ \text{cm}^3$

So, the volume of the ball is 65.548 cm³.

7 0

3 years ago

Select the two values of x that are roots of this equation 3x^2 + 1 =5x

Zina [86]

Answer:

x = 1.434 and x=0.232

Step-by-step explanation:

To find the root of the equation stated above we need to:

(1) Write the polynomial equation with zero on the right hand side:

$3x^{2} + 1 = 5x$ ⇒ $3x^{2} -5x + 1 = 0$

(2) Divide the whole equation by 3

$3x^{2} -5x + 1 = 0$ ⇒ $x^{2} -\frac{5}{3}x + \frac{1}{3}= 0$

(3) Use the quadratic formula to solve the quadratic equation:

The quadratic formula states that the two solutions for a quadratic equation is given by:

$\frac{-b±\sqrt{b^{2} - 4ac}}{2a}$ (1)

In this case, a = 1, b = $-\frac{5}{3}, c= \frac{1}{3}$

Substituiting a, b and c in equation (1) We get:

$\frac{-\frac{5}{3}±\sqrt{(-\frac{5}{3})^{2} - 4(1)(\frac{1}{3})}}{2(1)}$ (1)

The two solutions are:

x = 1.434 and x=0.232

8 0

3 years ago

I need help on my quiz!

Fantom [35]

I can’t see good this image

3 0

3 years ago

BD is the angle bisector of

AlexFokin [52]

Note: Let us consider, we need to find the $m\angle ABC$ and $m\angle DBC$ .

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The $m\angle ABC$ and $m\angle DBC$ .

Solution:

BD is the angle bisector of ABC. So,

$m\angle ABD=m\angle DBC$

$3x=x+20$

$3x-x=20$

$2x=20$

Divide both sides by 2.

$x=\dfrac{20}{2}$

$x=10$

Now,

$m\angle DBC=(x+20)^\circ$

$m\angle DBC=(10+20)^\circ$

$m\angle DBC=30^\circ$

And,

$m\angle ABC=(3x)^\circ+(x+20)^\circ$

$m\angle ABC=(4x+20)^\circ$

$m\angle ABC=(4(10)+20)^\circ$

$m\angle ABC=(40+20)^\circ$

$m\angle ABC=60^\circ$

Therefore, $m\angle DBC=30^\circ,m\angle ABD=30^\circ$ and $m\angle ABC=60^\circ$ .

8 0

3 years ago

The following table represents the altitude of a hiker climbing in Mountain over a 60 minute hike. Calculate the average rate of

Serggg [28]

Answer:

The correct answer is B. The rate of change is about 3 feet per minute

I hope this helped!

6 0

4 years ago