Partition the set A into 4 subsets:
{1, 8}, {2, 7}, {3, 6}, and {4, 5},
each consisting of two integers whose sum is 9. If 5 integers are selected from A,
then by the Pigeonhole Principle at least two must be from the same subset. But
then the sum of these two integers is 9.
Answer: 200ft
Step-by-step explanation:
43+43+57+57=200
Step-by-step explanation:
You need to solve for x.
You can do that by either setting both of the equations equal to each other. or Solve each one separately and subtract the EG equation from the EW to get GW
3.) 3, 4, 5
&
4.) 6, 8, 10
Those two are right triangles because when you add the squares of the first two it should give you the square root of the third number
a^2 + b^2 = c^2
So
3^2 + 4^2 = 5^2
9 + 16 = 25
25 = 25
6^2 + 8^2 = 10^2
36 + 64 = 100
100 = 100
Therefore they are right triangles
But 1 & 2 aren’t right triangles because when you add the squares of the first two number, it doesn’t equal to the square root of the third number.
Hope this helps!!
Answer:
times the numbers
Step-by-step explanation:
